我一直在使用 Swift 开发基于文本的冒险游戏。但是，我似乎无法更改特定类的默认值。

下面是允许我选择我的玩家类的类的代码

    import UIKit

    class ClassSelectionController: UIViewController
    {
        //Default class values
        var character = (0, 0, "", 0)

        override func viewDidLoad()
        {
                super.viewDidLoad()
                // Do any additional setup after loading the view.
        }

        //class button actions
        @IBAction func fighterBtn(_ sender: Any)
        {
                character = (50, 60, "Steal Sword", 18)
                performSegue(withIdentifier: "Character", sender: self)
        }

        @IBAction func wizerdBtn(_ sender: Any)
        {
                character = (25, 70, "Staff", 15)
                performSegue(withIdentifier: "Character", sender: self)
        }

        @IBAction func thiefBtn(_ sender: Any)
        {
                character = (30, 60, "Dagger", 18)
                performSegue(withIdentifier: "Character", sender: self)
        }

        @IBAction func archerBtn(_ sender: Any)
        {
                character = (50, 60, "Bow & Arrow", 16)
                performSegue(withIdentifier: "Character", sender: self)
        }


        override func prepare(for segue: UIStoryboardSegue, sender: (Any)?)
        {
                //code for segue
                var vc = segue.destination as! ViewController
                vc.finalCharacter = self.character
        }

    }

这是接收播放器类数据并显示它的类。

    import UIKit

    class ViewController: UIViewController
    {
            var finalCharacter = (0, 0, "", 0)
            //****************************************
            //Setup for outlets go between these lines
            //****************************************
            @IBOutlet weak var healthLabel: UILabel!
            @IBOutlet weak var damageLabel: UILabel!
            @IBOutlet weak var weaponLabel: UILabel!
            @IBOutlet weak var armorLabel: UILabel!
            @IBOutlet weak var storyLabel: UILabel!
            @IBOutlet weak var actionButton: UIButton!


            @IBOutlet weak var northBtn: UIButton!
            @IBOutlet weak var southBtn: UIButton!
            @IBOutlet weak var eastBtn: UIButton!
            @IBOutlet weak var westBtn: UIButton!

            //****************************************
            //Setup for outlets go between these lines
            //****************************************


            override func viewDidLoad()
            {
                    super.viewDidLoad()
                    // Do any additional setup after loading the view.

                    healthLabel.text = "Health: \(finalCharacter.0)"
                    damageLabel.text = "Damage: \(finalCharacter.1)"
                    weaponLabel.text = "Weapon: " + finalCharacter.2
                    armorLabel.text  = "Armor : \(finalCharacter.3)"
            }

            //****************************************
            //Setup for buttons go between these lines
            //****************************************
            @IBAction func actionButton(_ sender: Any)
            {

            }

            @IBAction func northButton(_ sender: Any)
            {

            }

            @IBAction func southButton(_ sender: Any)
            {

            }

            @IBAction func eastButton(_ sender: Any)
            {

            }

            @IBAction func westButton(_ sender: Any)
            {

            }
    //****************************************
    //Setup for buttons go between these lines
    //****************************************
    }

尽管我的代码目前没有显示它，但我确实在类按钮中放置了打印值，以便在我选择一个类时查看这些值是否发生了变化，并且我已经看到它们在按下按钮时确实发生了变化。我还查看了 ViewController 并更改了 finalCharacter 值，只是想看看这是否影响了什么，但事实并非如此。所以我有根据的猜测是问题必须出在 ClassSelectionController 中。

所以主要问题是我将单击巫师玩家类别，我希望弹出巫师的类别统计信息(即 25、70、“员工”、15)，但我只会获取 ClassSelectionController 中的默认值 (0, 0, "", 0)。

最佳答案

这里发生了什么，你有多个名为“Character”的 UIStoryboardSegue 链接到每个按钮

因此，当您按下按钮时，会在 Action 按钮之前调用 Segue，此外还会再次调用 UIStoryboardSegue(如果您将调试器放置在 viewDidLoad 你会看到它去了两次)。

解决方案

• 删除所有从按钮链接的UIStoryboardSegue
• 从 ClassSelectionController 到下一个 ViewController 创建一个新的 UIStoryboardSegue 并将其命名为 'Character'

您不需要更改代码中的任何内容，但应该添加安全检查

override func prepare(for segue: UIStoryboardSegue, sender: (Any)?)
    {
        if (segue.identifier == "Character") {
            let vc = segue.destination as! ViewController
            vc.finalCharacter = self.character
        }
    }

关于swift - 如何在 Swift 中的类之间正确发送值？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/55738979/