我想从我的 Android 应用请求一个带有 GET 参数的 URL 并读取响应。 在请求中，我必须添加一个 x-zip header 。

网址是这样的

http://example.com/getmethod.aspx?id=111&method=Test

有人可以为我提供代码吗？

有两点很重要:它是一个 GET 请求并且包含 x-zip header 。

编辑:

try {
    HttpClient client = new DefaultHttpClient();  
    String getURL = "http://example.com/getmethod.aspx?id=111&method=Test";
    HttpGet get = new HttpGet(getURL);
    get.setHeader("Content-Type", "application/x-zip");
    HttpResponse responseGet = client.execute(get);  
    HttpEntity resEntityGet = responseGet.getEntity();  
    if (resEntityGet != null) {  
        //do something with the response
        Log.i("GET ",EntityUtils.toString(resEntityGet));
    }
} catch (Exception e) {
    e.printStackTrace();
}

我尝试使用此代码，但我得到的代码带有 .net 错误:对象引用未设置为对象的实例... 我想，但我不确定如果对于 x-zip header ，我的代码中的 header 是否正常？

最佳答案

这是我们在应用中用来设置请求 header 的代码摘录。您会注意到我们仅在 POST 或 PUT 上设置 CONTENT_TYPE header ，但添加 header 的一般方法(通过请求拦截器)也用于 GET。

/**
 * HTTP request types
 */
public static final int POST_TYPE   = 1;
public static final int GET_TYPE    = 2;
public static final int PUT_TYPE    = 3;
public static final int DELETE_TYPE = 4;

/**
 * HTTP request header constants
 */
public static final String CONTENT_TYPE         = "Content-Type";
public static final String ACCEPT_ENCODING      = "Accept-Encoding";
public static final String CONTENT_ENCODING     = "Content-Encoding";
public static final String ENCODING_GZIP        = "gzip";
public static final String MIME_FORM_ENCODED    = "application/x-www-form-urlencoded";
public static final String MIME_TEXT_PLAIN      = "text/plain";

private InputStream performRequest(final String contentType, final String url, final String user, final String pass,
    final Map<String, String> headers, final Map<String, String> params, final int requestType) 
            throws IOException {

    DefaultHttpClient client = HTTPClientFactory.newClient();

    client.getParams().setParameter(HttpProtocolParams.USER_AGENT, mUserAgent);

    // add user and pass to client credentials if present
    if ((user != null) && (pass != null)) {
        client.getCredentialsProvider().setCredentials(AuthScope.ANY, new UsernamePasswordCredentials(user, pass));
    }

    // process headers using request interceptor
    final Map<String, String> sendHeaders = new HashMap<String, String>();
    if ((headers != null) && (headers.size() > 0)) {
        sendHeaders.putAll(headers);
    }
    if (requestType == HTTPRequestHelper.POST_TYPE || requestType == HTTPRequestHelper.PUT_TYPE ) {
        sendHeaders.put(HTTPRequestHelper.CONTENT_TYPE, contentType);
    }
    // request gzip encoding for response
    sendHeaders.put(HTTPRequestHelper.ACCEPT_ENCODING, HTTPRequestHelper.ENCODING_GZIP);

    if (sendHeaders.size() > 0) {
        client.addRequestInterceptor(new HttpRequestInterceptor() {

            public void process(final HttpRequest request, final HttpContext context) throws HttpException,
                IOException {
                for (String key : sendHeaders.keySet()) {
                    if (!request.containsHeader(key)) {
                        request.addHeader(key, sendHeaders.get(key));
                    }
                }
            }
        });
    }

    //.... code omitted ....//

}

关于java - 发送带有 header 的 HTTP GET 请求，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/6442791/