我有一个类似这样的查询

SELECT 
t.category, 
tc.product, 
tc.sub-product,
 count(*) as sales 
 FROM tg t, ttc tc
 WHERE t.value = tc.value
 GROUP BY t.category, tc.product, tc.sub-product;

现在在我的查询中，我想获得每个类别的前 10 名产品(按销售额排名)和每个类别我需要前 5 个子类别(按销售额排名)

你可以假设问题陈述是这样的:

获取每个类别销售额前 10 名的产品，并针对每个产品获取销售额前 5 名的子产品。

• 这里的类别可以是书籍
• 产品可以是哈利·波特的书
• 子产品可以是 HarryPorter 系列 5

示例输入数据格式

category |product |subproduct |Sales [count (*)]

abc   test1    test11     120

abc   test1    test11     100

abc   test1    test11     10

abc   test1    test11     10

abc   test1    test11     10

abc   test1    test11     10

abc   test1    test12     10

abc   test1    test13     8

abc   test1    test14     6

abc   test1    test15     5

abc   test2    test21     80

abc   test2    test22     60

abc   test3    test31     50

abc   test3    test32     40

abc   test4    test41     30

abc   test4    test42     20

abc   test5    test51     10

abc   test5    test52     5 

abc   test6    test61     5 

|

|

|

bcd   test2    test22     10 

xyz   test3    test31     5 

xyz   test3    test32     3 

xyz   test4    test41     2

输出将是“

top 5 rf for (abc) -> abc,test1(289) abc,test2 (140), abc test3 (90), abc test4(50) , abc test5 (15)

top 5 rfm for (abc,test1) -> test11(260),test12(10),test13(8),test14(6),test15(5) and so on

我的查询失败了，因为结果非常庞大。我正在阅读有关等级的 oracle 分析函数。有人可以帮助我使用分析函数修改此查询。任何其他方法也可以。

我指的是这个 http://www.orafaq.com/node/55 .但是无法为此获得正确的 sql 查询。

如有任何帮助，我们将不胜感激..我在这个问题上被困了 2 天:(

最佳答案

可能有一些原因不使用分析函数，而是单独使用分析函数:

select am, rf, rfm, rownum_rf2, rownum_rfm
from
(
    -- the 3nd level takes the subproduct ranks, and for each equally ranked
    -- subproduct, it produces the product ranking
    select am, rf, rfm, rownum_rfm,
      row_number() over (partition by rownum_rfm order by rownum_rf) rownum_rf2
    from
    (
        -- the 2nd level ranks (without ties) the products within
        -- categories, and subproducts within products simultaneosly
        select am, rf, rfm,
          row_number() over (partition by am order by count_rf desc) rownum_rf,
          row_number() over (partition by am, rf order by count_rfm desc) rownum_rfm
        from
        (
            -- inner most query counts the records by subproduct
            -- using regular group-by. at the same time, it uses
            -- the analytical sum() over to get the counts by product
            select tg.am, ttc.rf, ttc.rfm,
              count(*) count_rfm,
              sum(count(*)) over (partition by tg.am, ttc.rf) count_rf
            from tg inner join ttc on tg.value = ttc.value
            group by tg.am, ttc.rf, ttc.rfm
        ) X
    ) Y
    -- at level 3, we drop all but the top 5 subproducts per product
    where rownum_rfm <= 5   -- top  5 subproducts
) Z
-- the filter on the final query retains only the top 10 products
where rownum_rf2 <= 10  -- top 10 products
order by am, rownum_rf2, rownum_rfm;

我使用 rownum 而不是 rank，所以你永远不会得到平局，或者换句话说，平局将随机决定。如果数据不够密集(前 10 个产品中的任何一个都少于 5 个子产品——它可能会显示其他一些产品的子产品)，这也不起作用。但如果数据密集(已建立的大型数据库)，查询应该可以正常工作。

select am, rf, rfm, count_rf, count_rfm, rownum_rf, rownum_rfm
from
(
    -- next join the top 10 products to the data again to get
    -- the subproduct counts
    select tg.am, tg.rf, ttc.rfm, tg.count_rf, tg.rownum_rf, count(*) count_rfm,
        ROW_NUMBER() over (partition by tg.am, tg.rf order by 1 desc) rownum_rfm
    from (
        -- first rank all the products
        select tg.am, tg.value, ttc.rf, count(*) count_rf,
            ROW_NUMBER() over (order by 1 desc) rownum_rf
        from tg
        inner join ttc on tg.value = ttc.value
        group by tg.am, tg.value, ttc.rf
        order by count_rf desc
        ) tg
    inner join ttc on tg.value = ttc.value and tg.rf = ttc.rf
    -- filter the inner query for the top 10 products only
    where rownum_rf <= 10
    group by tg.am, tg.rf, ttc.rfm, tg.count_rf, tg.rownum_rf
) X
-- filter where the subproduct rank is in top 5
where rownum_rfm <= 5
order by am, rownum_rf, rownum_rfm;

列:

count_rf : count of sales by product
count_rfm : count of sales by subproduct
rownum_rf : product rank within category (rownumber - without ties)
rownum_rfm : subproduct rank within product (without ties)

关于sql - 获取每个类别的前 10 名产品，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/4966905/