我目前正在使用从那里下载和解析的 xml。我想直接从 url 本身来做。我怎样才能做到这一点？

我在下面添加了我正在使用的代码段。请帮忙提供一个 fragment 或例子。谢谢。

DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
File file = new File(this.getFilesDir(), FILE_EXTRACTED);
Document dom = builder.parse(file);
Element root = dom.getDocumentElement();
root.normalize();

最佳答案

使用下面的代码从android中的url解析xml

public class XMLParsingDOMExample extends Activity {
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);

        /** Create a new layout to display the view */
        LinearLayout layout = new LinearLayout(this);
        layout.setOrientation(1);

        /** Create a new textview array to display the results */
        TextView name[];
        TextView website[];
        TextView category[];

        try {

            URL url = new URL("http://www.androidpeople.com/wp-content/uploads/2010/06/example.xml");
            DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
            DocumentBuilder db = dbf.newDocumentBuilder();
            Document doc = db.parse(new InputSource(url.openStream()));
            doc.getDocumentElement().normalize();

            NodeList nodeList = doc.getElementsByTagName("item");

            /** Assign textview array lenght by arraylist size */
            name = new TextView[nodeList.getLength()];
            website = new TextView[nodeList.getLength()];
            category = new TextView[nodeList.getLength()];

            for (int i = 0; i < nodeList.getLength(); i++) {

                Node node = nodeList.item(i);

                name[i] = new TextView(this);
                website[i] = new TextView(this);
                category[i] = new TextView(this);

                Element fstElmnt = (Element) node;
                NodeList nameList = fstElmnt.getElementsByTagName("name");
                Element nameElement = (Element) nameList.item(0);
                nameList = nameElement.getChildNodes();
                name[i].setText("Name = " + ((Node) nameList.item(0)).getNodeValue());

                NodeList websiteList = fstElmnt.getElementsByTagName("website");
                Element websiteElement = (Element) websiteList.item(0);
                websiteList = websiteElement.getChildNodes();
                website[i].setText("Website = " + ((Node) websiteList.item(0)).getNodeValue());

                category[i].setText("Website Category = " + websiteElement.getAttribute("category"));

                layout.addView(name[i]);
                layout.addView(website[i]);
                layout.addView(category[i]);
            }
        } catch (Exception e) {
            System.out.println("XML Pasing Excpetion = " + e);
        }

        /** Set the layout view to display */
        setContentView(layout);

    }
}

关于android - 我如何从android中的url解析xml？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/12065951/