表:contact、company 和具有自定义数据透视属性的关系表 company_contact (company_id, contact_id, is_main)

Company 和 Contact 具有多对多关系(belongsTo 在两个模型上)。

检索公司联系人时的预期输出:

{
    "data": [
        {
            "id": 1,
            "name": "JohnDoe",
            "is_main": false
        },
        {
            "id": 2,
            "name": "JaneDoe",
            "is_main": true
        }
    ]
}

当我使用 ?include=companies 检索联系人列表时的预期输出:

{
    "data": [
        {
            "id": 1,
            "name": "John Doe",
            "companies": {
                "data": [
                    {
                        "id": 501,
                        "name": "My Company",
                        "is_main": true
                    },
                    {
                        "id": 745,
                        "name": "Another Company",
                        "is_main": false
                    }
                ]
            }
        },
        {
            "id": 2,
            "name": "Jane Doe",
            "companies": {
                "data": [
                    {
                        "id": 999,
                        "name": "Some Company",
                        "is_main": true
                    }
                ]
            }
        }
    ]
}

添加数据透视表属性的最佳方式是什么？如果设置了属性，在公司转换器上添加 is_main 似乎不是很干净。

对于第一个示例，我正在考虑使用参数 ?include=company_relationship:company_id(1) ，例如:

public function includeCompanyRelationship(Contact $contact, ParamBag $params) {
    // .. retrieve the pivot table data here
    $is_main = $company->is_main;

    // but now I would need another transformer, when what I actually want is to push the value on the main array (same level)

    return $this->item(??, ??);
}

我了解如何检索数据透视数据(相关:Laravel 5.1 - pivot table between three tables, better option?)但不是将其添加到 https://github.com/thephpleague/fractal 中的最佳方式转换器逻辑。

我已经有一个 ContactTransformer 和 CompanyTransformer，但如果我将 is_main 添加到 CompanyTransformer，我进行的所有调用(与联系人相关或不相关)也将需要该属性。

最佳答案

如果我没看错的话，您可以使用一个 CompanyTransformer 来处理您是否希望设置 is_main 属性，但前提是 $contact 参数被传递给它的构造函数，大致如下:

class CompanyTransformer extends TransformerAbstract
{
    public function __construct(Contact $contact = null)
    {
        $this->contact = $contact;
    }

    public function transform(Company $company)
    {
        $output = [
            'id' => $company->id,
            'name' => $company->name,
        ];

        if($this->contact) {
            // This step may not be necessary, but I don't think the pivot data 
            // will be available on the $company object passed in
            $company = $this->contacts->find($company->id);
            // You may have to cast this to boolean if that is important
            $output['is_main'] = $company->pivot->is_main;
        }

        return $output;
    }
}

然后在您的 includeCompanyRelationship 中传入带有参数的新 CompanyTransformer:

public function includeCompanyRelationship(Contact $contact) 
{
    $companies = $contact->companies;

    return $this->collection($companies, new CompanyTransformer($contact));
}

无论您是直接调用您的 companies 端点，还是在嵌入公司关系数据时调用联系人的端点，这都应该有效。

关于php - Laravel 5.1 和分形 : including pivot table data on the transformer，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/32697260/