我创建了一个 Web 服务来在 iOS 应用程序和 Joomla 网站之间进行通信，我使用 GET 方法在移动应用程序和 Web 服务之间以及 Web 服务和 Controller (PHP) 之间进行通信执行工作并返回数据的文件)，但我没有找到如何将实现转换为 POST 方法，这里是实际系统:

ws.php :这是网络服务(简单示例)

<?php 
      $id = $_GET['id'] ; // get the data from the URL

// here i make testes

// then I redirect to the controller of the Joomla component that receive 
// the call of the request the URL is actually the attribute "action" of 
// an existing HTML Form that implement the login system, I added a 
// parameter called web service to help me to modify the controller 
// to make the difference between a normal call and a web service call

header("Location: index.php?option=com_comprofiler&task=login&ws=1&id=1");
?> 

Controller.php :网络服务调用的接收者和网络调用(来自浏览器)

<?php 
// code added by me, in the existent controller of the component
// it was waiting for a form submitting, so I got to convert my data to POST here

if (isset($_GET['ws'])) // it's a web service call 
{
   $_POST['id'] = $_GET['id'] ; 

   // do the task ... 

   if ($correctLogin) // just an example 
     echo "1"
   else 
     echo '0';
}
?>

我没有放真正的实现，只是一个简单的系统示例，但是是一样的

手机通话

 NSURL *url = [[NSURL alloc]initWithString:@"http://localhost/ws.php?id=1"];

 NSData *dataUrl= [NSData dataWithContentsOfURL:url];

 NSString *str = [[NSString alloc]initWithData:dataUrl 
                                      encoding:NSUTF8StringEncoding];

if(![str isEqualToString:@"0"])
    NSLog(@"connected");
else
    NSLog(@"not connected");

所以我不想使用 GET 方法，我只想使用 POST 从手机接收数据，并使用 POST 将数据发送到 Controller ，什么是最好的解决方案？

最佳答案

如果您希望您的应用使用 POST 方法发送数据，那么我就是这段代码。希望对您有所帮助。

它需要在字典对象中发送的数据。 将要发送的数据编码为 POST 然后返回响应(如果你想要字符串格式的结果，你可以使用 [[NSString alloc] initWithData:dresponse encoding: NSASCIIStringEncoding]; 返回数据时)

-(NSData*) getData:(NSDictionary *) postDataDic{

    NSData *dresponse = [[NSData alloc] init];

    NSURL *nurl = [NSURL URLWithString:url];
    NSDictionary *postDict = [[NSDictionary alloc] initWithDictionary:postDataDic];
    NSData *postData = [self encodeDictionary:postDict];

    // Create the request
    NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:nurl];
    [request setHTTPMethod:@"POST"]; // define the method type
    [request setValue:[NSString stringWithFormat:@"%d", postData.length] forHTTPHeaderField:@"Content-Length"];
    [request setValue:@"application/x-www-form-urlencoded charset=utf-8" forHTTPHeaderField:@"Content-Type"];
    [request setHTTPBody:postData];

        // Peform the request
        NSURLResponse *response;
        NSError *error = nil;

        dresponse = [NSURLConnection sendSynchronousRequest:request  
                                                     returningResponse:&response
                                                                 error:&error];

    return dresponse;
}

此方法为 POST 准备字典数据

- (NSData*)encodeDictionary:(NSDictionary*)dictionary {
    NSMutableArray *parts = [[NSMutableArray alloc] init];
    for (NSString *key in dictionary) {
        NSString *encodedValue = [[dictionary objectForKey:key] stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
        NSString *encodedKey = [key stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]; 
        NSString *part = [NSString stringWithFormat: @"%@=%@", encodedKey, encodedValue];
        [parts addObject:part];
    }
    NSString *encodedDictionary = [parts componentsJoinedByString:@"&"];
    return [encodedDictionary dataUsingEncoding:NSUTF8StringEncoding];
}

关于ios - 将 Web 服务从 GET 转换为 POST，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/14791169/