我有 Cisco 为 IOS XE 路由器提供的 XML 模式。当运行命令 'show ip access-list test | format' 在路由器的 cli 中，它吐出一个 XML 片段，应该验证这个模式。然而事实并非如此。相反，我收到错误“:没有匹配的全局声明可用于验证根”

Cisco 提供的架构通过运行 'show xsd-format cli show ip access-lists' 提取，如此处推荐 http://www.cisco.com/c/en/us/td/docs/ios-xml/ios/xmlpi/command/xmlpi-cr-book/xmlpi-cr-p1.html#GUID-33CB3BAB-25B4-4FAD-9741-C7AFB483F701如下图所示:

<?xml version="1.0" encoding="UTF-8"?>
  <xsd:schema elementFormDefault="qualified" attributeFormDefault="unqualified" xmlns:xsd="http://www.w3.org/2001/XMLSchema" >
    <xsd:complexType name="ShowAccesslists_def">
      <xsd:sequence>
        <xsd:element ref="SpecVersion" minOccurs="0" />
        <xsd:choice minOccurs="0" maxOccurs="unbounded">
          <xsd:element ref="Info" />
          <xsd:element name="Access-List" minOccurs="0" maxOccurs="1">
            <xsd:complexType>
              <xsd:sequence>
                <xsd:element name="Type" minOccurs="0" maxOccurs="1" type="xsd:string" />
                <xsd:element name="Name" minOccurs="0" maxOccurs="1" type="xsd:string" />
                <xsd:element name="DenyFilter" minOccurs="0" maxOccurs="1">
                  <xsd:complexType>
                    <xsd:sequence>
                      <xsd:element name="Filter" minOccurs="0" maxOccurs="1" type="xsd:string" />
                    </xsd:sequence>
                  </xsd:complexType>
                </xsd:element>
                <xsd:element name="PermitFilter" minOccurs="0" maxOccurs="1">
                  <xsd:complexType>
                    <xsd:sequence>
                      <xsd:element name="Filter" minOccurs="0" maxOccurs="1" type="xsd:string" />
                    </xsd:sequence>
                  </xsd:complexType>
                </xsd:element>
              </xsd:sequence>
            </xsd:complexType>
          </xsd:element>
        </xsd:choice>
      </xsd:sequence>
    </xsd:complexType>
    <xsd:element name="SpecVersion" type="xsd:string" />
    <xsd:element name="Info" type="xsd:string" />
    <xsd:element name="ShowAccesslists" type="ShowAccesslists_def" />
  </xsd:schema>

路由器吐出的 XML 片段是:

<?xml version="1.0" encoding="UTF-8"?>
   <ShowAccesslists xmlns="ODM://built-in//show_access-lists">
    <Access-List>
      <Type>Extended IP</Type>
      <Name>test</Name>
      <PermitFilter>
        <Filter>10 permit ip any any</Filter>
      </PermitFilter>
      <PermitFilter>
        <Filter>20 permit tcp 0.0.0.1 255.255.255.0 any</Filter>
      </PermitFilter>
      <PermitFilter>
        <Filter>40 permit tcp host 10.22.1.128 10.11.79.0 0.0.0.255 eq domain</Filter>
      </PermitFilter>
      <PermitFilter>
        <Filter>50 permit tcp host 10.22.1.128 eq domain 10.11.79.0 0.0.0.255</Filter>
      </PermitFilter>
    </Access-List>
  </ShowAccesslists>

架构是否损坏？我如何让它进行验证？

最佳答案

答案取决于您是希望更改 XML 还是 XSD...

更改 XML

根据您的 XSD，您的 XML 不应该在命名空间中，也不应该有多个 PermitFilter 元素。

因此，如果您希望保持 XSD 不变，则以下更新的 XML 将成功验证您的 XSD。

<?xml version="1.0" encoding="UTF-8"?>
<ShowAccesslists>
  <Access-List>
    <Type>Extended IP</Type>
    <Name>test</Name>
    <PermitFilter>
      <Filter>10 permit ip any any</Filter>
    </PermitFilter>
  </Access-List>
</ShowAccesslists>

改变XSD

您的 XML 位于命名空间中并具有多个 PermitFilter 元素。

如果您希望保持 XML 不变，请将 targetNamespace 添加到您的 XSD，为该命名空间定义一个命名空间前缀，并在引用该命名空间中的组件时使用该前缀。以下更新的 XSD 准确地显示了如何执行此操作并将成功验证您的 XML:

<?xml version="1.0" encoding="UTF-8"?>
<xsd:schema elementFormDefault="qualified" attributeFormDefault="unqualified" 
            xmlns:xsd="http://www.w3.org/2001/XMLSchema" 
            xmlns:sal="ODM://built-in//show_access-lists" 
            targetNamespace="ODM://built-in//show_access-lists">
  <xsd:complexType name="ShowAccesslists_def">
    <xsd:sequence>
      <xsd:element ref="sal:SpecVersion" minOccurs="0" />
      <xsd:choice minOccurs="0" maxOccurs="unbounded">
        <xsd:element ref="sal:Info" />
        <xsd:element name="Access-List" minOccurs="0" maxOccurs="1">
          <xsd:complexType>
            <xsd:sequence>
              <xsd:element name="Type" minOccurs="0" maxOccurs="1" type="xsd:string" />
              <xsd:element name="Name" minOccurs="0" maxOccurs="1" type="xsd:string" />
              <xsd:element name="DenyFilter" minOccurs="0" maxOccurs="1">
                <xsd:complexType>
                  <xsd:sequence>
                    <xsd:element name="Filter" minOccurs="0" maxOccurs="1" type="xsd:string" />
                  </xsd:sequence>
                </xsd:complexType>
              </xsd:element>
              <xsd:element name="PermitFilter" minOccurs="0" maxOccurs="unbounded">
                <xsd:complexType>
                  <xsd:sequence>
                    <xsd:element name="Filter" minOccurs="0" maxOccurs="1" type="xsd:string" />
                  </xsd:sequence>
                </xsd:complexType>
              </xsd:element>
            </xsd:sequence>
          </xsd:complexType>
        </xsd:element>
      </xsd:choice>
    </xsd:sequence>
  </xsd:complexType>
  <xsd:element name="SpecVersion" type="xsd:string" />
  <xsd:element name="Info" type="xsd:string" />
  <xsd:element name="ShowAccesslists" type="sal:ShowAccesslists_def" />
</xsd:schema>

关于XML 验证 没有匹配的全局声明可用于验证根，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/43277806/