我正在使用 Play 2.5 构建一个简单的应用程序。为了获得更好的性能，我将 Akka 分块响应与 Java 8 CompletionStage 策略结合使用。下面是生成分块响应的代码(不使用 ComperableFuture 时工作正常):

@Singleton
public class AbstractSource {

    public Source<ByteString, ?> getChunked(String html) {

        return Source.<ByteString>actorRef(256, OverflowStrategy.dropNew())
                .mapMaterializedValue(sourceActor -> {
                    sourceActor.tell(ByteString.fromString(html), null);
                    sourceActor.tell(new Status.Success(NotUsed.getInstance()), null);
                    return null;
                });

    }

}

这是我的 Controller :

@Singleton
@AddCSRFToken
public class Application extends Controller {

    @Inject
    private AbstractSource abstractSource;

    public CompletionStage<Result> index() {


        CompletionStage<Source<ByteString, ?>> source = CompletableFuture.supplyAsync(() -> 
                                                  abstractSource.getChunked(index.render(CSRF.getToken(request()).map(t -> 
                                                    t.value()).orElse("no token")).body()
                                                   )
                                                );

        return source.thenApply( chunks -> ok().chunked(chunks));

    }

}

现在，当我运行该应用程序时，它会抛出以下异常:

play.api.http.HttpErrorHandlerExceptions$$anon$1: Execution exception[[CompletionException: java.lang.RuntimeException: There is no HTTP Context available from here.]]
    at play.api.http.HttpErrorHandlerExceptions$.throwableToUsefulException(HttpErrorHandler.scala:269)
    at play.api.http.DefaultHttpErrorHandler.onServerError(HttpErrorHandler.scala:195)
    at play.api.GlobalSettings$class.onError(GlobalSettings.scala:160)
    at play.api.DefaultGlobal$.onError(GlobalSettings.scala:188)
    at play.api.http.GlobalSettingsHttpErrorHandler.onServerError(HttpErrorHandler.scala:98)
    at play.core.server.netty.PlayRequestHandler$$anonfun$2$$anonfun$apply$1.applyOrElse(PlayRequestHandler.scala:99)
    at play.core.server.netty.PlayRequestHandler$$anonfun$2$$anonfun$apply$1.applyOrElse(PlayRequestHandler.scala:98)
    at scala.concurrent.Future$$anonfun$recoverWith$1.apply(Future.scala:344)
    at scala.concurrent.Future$$anonfun$recoverWith$1.apply(Future.scala:343)
    at scala.concurrent.impl.CallbackRunnable.run(Promise.scala:32)
Caused by: java.util.concurrent.CompletionException: java.lang.RuntimeException: There is no HTTP Context available from here.
    at java.util.concurrent.CompletableFuture.encodeThrowable(CompletableFuture.java:273)
    at java.util.concurrent.CompletableFuture.completeThrowable(CompletableFuture.java:280)
    at java.util.concurrent.CompletableFuture$AsyncSupply.run(CompletableFuture.java:1592)
    at java.util.concurrent.CompletableFuture$AsyncSupply.exec(CompletableFuture.java:1582)
    at java.util.concurrent.ForkJoinTask.doExec(ForkJoinTask.java:289)
    at java.util.concurrent.ForkJoinPool$WorkQueue.runTask(ForkJoinPool.java:1056)
    at java.util.concurrent.ForkJoinPool.runWorker(ForkJoinPool.java:1692)
    at java.util.concurrent.ForkJoinWorkerThread.run(ForkJoinWorkerThread.java:157)
Caused by: java.lang.RuntimeException: There is no HTTP Context available from here.
    at play.mvc.Http$Context.current(Http.java:57)
    at play.mvc.Controller.request(Controller.java:36)
    at com.mabsisa.ui.web.controllers.Application.lambda$index$1(Application.java:31)
    at java.util.concurrent.CompletableFuture$AsyncSupply.run(CompletableFuture.java:1590)
    ... 5 common frames omitted

我没有在任何地方使用 HTTP 上下文，所以我不明白为什么这不起作用。当返回带有分块响应的正常结果时，相同的代码有效。请帮忙解决这个问题

最佳答案

在处理 CompletableFuture/CompletionStage 时，您必须提供 HTTP 执行上下文。在 Scala 中，上下文信息通过隐式传递，这些在 Java 中不可用 - 这就是 Play 使用 ThreadLocal 的原因。

但是在切换线程时您可能会丢失此信息，这就是您遇到问题的原因。您可能认为您没有访问 HTTP 上下文，但实际上您访问了 - 您正在使用 request()。

因此您必须更改代码以将 supplyAsync 与执行器一起使用:

https://docs.oracle.com/javase/8/docs/api/java/util/concurrent/CompletableFuture.html#supplyAsync-java.util.function.Supplier-java.util.concurrent.Executor-

来自这里:

CompletableFuture.supplyAsync(() -> abstractSource.getChunked(index.render(CSRF.getToken(request()).map(t -> 
                                                    t.value()).orElse("no token")).body()
                                                   )
                                                );

为此:

CompletableFuture.supplyAsync(() -> abstractSource.getChunked(index.render(CSRF.getToken(request()).map(t -> 
                                                    t.value()).orElse("no token")).body()
                                                   )
                                                , ec.current());

ec 是你的上下文:@Inject HttpExecutionContext ec;

关于java - Play Framework 2.5 JavaAsync 抛出 CompletionException，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/36236209/