给定路径 X 或 apache vhosts 配置文件的副本，我将如何使用 PHP 解析该文件？

例如给定一个包含具有 Apache vhosts 配置内容的字符串的变量，我将如何获得托管域/子域别名的列表？

例如，给定:

#
# Use name-based virtual hosting.
#
NameVirtualHost *:80



<VirtualHost *:80>
    ServerAdmin contact@tomjn.com
    DocumentRoot "/srv/www/localhost/

    ServerName 127.0.0.1
    ServerAlias localhost
    CustomLog "/srv/www/logs/localhost-access_log.log" combined
    ErrorLog "/srv/www/logs/localhost-error_log.log"

    <Directory "/srv/www/localhost">
        Options Indexes FollowSymLinks Includes ExecCGI
        AllowOverride All
        Order allow,deny
        Allow from all
    </Directory>
</VirtualHost>

<VirtualHost *:80>
    ServerAdmin contact@tomjn.com
    DocumentRoot "/srv/www/2.7.localhost.com/

    ServerName 2.7.localhost.com
    ServerAlias 2.7.localhost.com
    CustomLog "/srv/www/logs/2.7.localhost.com-access_log.log" combined
    ErrorLog "/srv/www/logs/2.7.localhost.com-error_log.log"

    <Directory "/srv/www/2.7.localhost.com">
        Options Indexes FollowSymLinks Includes ExecCGI
        AllowOverride All
        Order allow,deny
        Allow from all
    </Directory>
</VirtualHost>

我如何得到这个输出:

• 本地主机
• 2.7.localhost.com

这是用 Python 编写的非常接近的东西:

http://www.poldylicious.de/system/files/apacheconfig.py.txt

最佳答案

# Get Vhosts files
$path       = '/etc/apache2/sites-enabled'; # change to suit your needs
$a_directory = scandir($path);
$a_conf_files = array_diff($a_directory, array('..', '.'));
$info = array(); $x=0;

foreach($a_conf_files as $conf_file){
 $Thisfile   = fopen($path .'/'.$conf_file, 'r')or die('No open ups..');

    while(!feof($Thisfile)){
        $line = fgets($Thisfile);
        $line = trim($line);

       // CHECK IF STRING BEGINS WITH ServerAlias
        $tokens = explode(' ',$line);

        if(!empty($tokens)){
            if(strtolower($tokens[0]) == 'servername'){
                $info[$x]['ServerName'] = $tokens[1];
            }
            if(strtolower($tokens[0]) == 'documentroot'){
                $info[$x]['DocumentRoot'] = $tokens[1];
            }
            if(strtolower($tokens[0]) == 'errorlog'){
                $info[$x]['ErrorLog'] = $tokens[1];
            }
            if(strtolower($tokens[0]) == 'serveralias'){
                $info[$x]['ServerAlias'] = $tokens[1];
            }

        }else{
            echo "Puked...";
        }
    }

fclose($file);
$x++;
}

print_r($info);

输出:

Array
(
    [0] => Array
        (
            [ServerName] => bootstrap
            [ServerAlias] => BootstrapProject
            [DocumentRoot] => /data/sites/bootstrap/htdocs
            [ErrorLog] => /data/sites/bootstrap/log/error.log
        )

    [1] => Array
        (
            [ServerName] => localhost
            [ServerAlias] => dfs
            [DocumentRoot] => /data/sites/scott/htdocs
            [ErrorLog] => /data/sites/scott/log/error.log
        )

    [2] => Array
        (
            [ServerName] => wordpress
            [ServerAlias] => wordpress
            [DocumentRoot] => /data/sites/wordpress/public_html
            [ErrorLog] => /data/sites/wordpress/log/error.log
        )

)

关于php - 解析 Apache VHosts 以获取域和文件夹路径列表，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/14216449/