我想使用 JaxB 将一些非常讨厌的 XML 解码为 java 对象。到目前为止，大部分内容看起来都非常简单 - 但我有点坚持这一点:

            <assets>
                <asset type="fixed">74,414</asset>
                <asset type="current">1,022,069</asset>
                <asset type="other">0</asset>
                <total type="assets">1,096,483</total>
            </assets>

这是dtd的相关部分

<!ELEMENT assets (asset|total)*> <!ELEMENT asset (#PCDATA)> <!ATTLIST asset type CDATA #REQUIRED> <!ELEMENT total (#PCDATA)> <!ATTLIST total type CDATA #REQUIRED>

有什么想法吗？还是我应该为此放弃尝试使用 JAXB？

谢谢

最佳答案

查看 XML 和 DTD，我创建了结构的 XSD:

<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" 
  elementFormDefault="qualified">
  <xs:element name="assets">
    <xs:complexType>
      <xs:sequence>
        <xs:element maxOccurs="unbounded" ref="asset"/>
        <xs:element maxOccurs="unbounded" ref="total"/>
      </xs:sequence>
    </xs:complexType>
  </xs:element>
  <xs:element name="asset">
    <xs:complexType mixed="true">
      <xs:attribute name="type" use="required" type="xs:string"/>
    </xs:complexType>
  </xs:element>
  <xs:element name="total">
    <xs:complexType mixed="true">
      <xs:attribute name="type" use="required" type="xs:string"/>
    </xs:complexType>
  </xs:element>
</xs:schema>

使用 xjc 从 XSD 生成带有 JAXB 绑定(bind)注释的 Java 类。然后使用解码器将其解码为 Java 对象。

编辑

生成的 Java 类:

import java.util.ArrayList;
import java.util.List;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;
import javax.xml.bind.annotation.XmlType;
import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlValue;

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "", propOrder = {
    "asset",
    "total"
})
@XmlRootElement(name = "assets")
public class Assets {

    @XmlElement(required = true)
    protected List<Asset> asset;
    @XmlElement(required = true)
    protected List<Total> total;

    public List<Asset> getAsset() {
        if (asset == null) {
            asset = new ArrayList<Asset>();
        }
        return this.asset;
    }

    public List<Total> getTotal() {
        if (total == null) {
            total = new ArrayList<Total>();
        }
        return this.total;
    }

}

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "", propOrder = {
    "content"
})
@XmlRootElement(name = "asset")
public class Asset {

    @XmlValue
    protected String content;
    @XmlAttribute(required = true)
    protected String type;

    public String getContent() {
        return content;
    }

    public void setContent(String value) {
        this.content = value;
    }

    public String getType() {
        return type;
    }

    public void setType(String value) {
        this.type = value;
    }

}

@XmlAccessorType(XmlAccessType.FIELD)
@XmlType(name = "", propOrder = {
    "content"
})
@XmlRootElement(name = "total")
public class Total {

    @XmlValue
    protected String content;
    @XmlAttribute(required = true)
    protected String type;

    public String getContent() {
        return content;
    }

    public void setContent(String value) {
        this.content = value;
    }

    public String getType() {
        return type;
    }

    public void setType(String value) {
        this.type = value;
    }

}

关于java - JAXB - 如何解码此 XML？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/3206151/