这是一个关于为一组并行数据生成图像或任何其他表示的问题。不是关于绘图或 GUI 编程，而是计算位置。
首先，我将解释一下我现在所处的位置，第二张图片和示例显示了我的问题。

当前状态

exampleOne-Easy http://www.wargsang.de/text3935.png

我有一个一维的对象，但它们是通过将它们放在平行的“线”上来对齐的。让我们称这种一维对象为“事件”，它以“持续时间”为时间单位。
这些事件有一个变体，什么都不发生，对象没有数据但有持续时间；一个“间隙”对象。

所以我们得到了一个由事件和间隙组成的模拟对象的时间表，作为三个对象列表很容易处理。
可视化也很简单:遍历列表并根据其持续时间绘制每个对象。

class Event():
    def __init__(self, duration, displacement = 0):  #displacement is explained in the second example and the core problem of this question
        self.duration = duration
        self.displacement = displacement
        #additional data

    def self.draw(self, start_coordinate):
        """draw duration * 10 pixels in black"""
        #drawing code using start_coordinate to place the drawn object. see example graphic
        return duration * 10


class Gap():
    def __init__(self, duration, displacement = 0):
        self.duration = duration
        self.displacement = displacement
        #no data

    def self.draw(self, start_coordinate):
        """draw duration * 10 pixels in transparent"""
        #drawing code using start_coordinate to place the drawn object. see example graphic
        return duration * 10

row_one = [Event(1), Gap(1), Event(1), Gap(1), Event(1), Gap(1), Event(2)]
row_two = [Event(1), Gap(2), Event(1), Event(1), Gap(1), Event(1), Gap(1), ]
row_thr = [Gap(1), Event(1), Gap(1), Event(1), Gap(1), Event(3),]

timetable = [row_one, row_two, row_thr]

for row in timetable:
    pixelcounter = 0 # the current position.
    for item in row:
        ret = item.draw(pixelcounter) #draw on the current position. Get how width the item was
        pixelcounter += ret #save width for the next iteration        
    #instructions to move the "drawing cursor" down a few pixels so the next row does not overlap.     

row_one = [ Event(1), #1
            Event(0,1), Event(1), #2
            Gap(1), #3
            Event(1), #4
            Gap(1), #5
            Event(0,1), Event(1), #6
            Event(1), #7
            ] 
row_two = [ Event(1), #1
            Event(1), #2
            Gap(1), #3
            Event(1, 0.5), #4, 0,5 is not important. we can also simply to just ints. The important bit is that it has both values.
            Event(1), #5
            Event(1), #6
            Event(1), #7
            ] 
row_thr = [ Event(1), #1
            Event(1), #2
            Event(1), #3            
            Event(1), #4
            Event(1), #5            
            Event(0,1), Event(0,1), Event(1), #6   #Please pay attention to this case.
            Event(1), #7
            ] 

最佳答案

我不完全确定，但我认为你想要的是:

0 123 4  567
AbC.D .e FG
A B.CcD  EF
A BCD EfgHI

0  12
AAa
Aa B
AaaB

                         11    11  1 1     1     1  1   1  22 22   2     2  22  22   33    333    3  3  3 3   3 4   44444  4   4   4  45
    01 2 34   5678    9  01    23  4 5     6     7  8   9  01 23   4     5  67  89   01    234    5  6  7 8   9 0   12345  6   7   8  90
    AAAA  BB   CCC  dd..  EEe   Fff..      GGGGGg           ....         ...    HHH   ....        IIii  JJJ     ...   KKK  LLLLl
abbbCCC  DDDDDdd ..      EEEEE       Fff   GGG          HHH   IIIii      JJJjj  KKKK       LLLl   Mno.  PPP    qR   SSSSSs TT   uuuVV
    ...  AAAAA   BBB      CC    DDDD             ...       EE FFFF          GHhhIIII       JJ.    K  Lll.m....       NNNO  ....
    ......     AAAA      ..    ....        BBB          CCCCCc     DDDDDd        Ee  FFFFff  G hhhIIIII         JJJ   KLLLLLll        M
    .. AAA    BBBCcc  DD  EE    ..   FFF           gH   IIIIIi     J     KKk LL  MMMMM       NNNNNn           OOo   PPQQQQ  rrr...
    AAAAa .   BBBBbb  CCCCC        DDDDDd            eeeFFFFF      GG       HH  .....       IIIII         JJ    K   LM.NNNNN          .
    AAAaaBBB   CCCcc  DDDDDdd      EeFF          ...       GGgHHHH          III  JJJJ       KKK    llMMMm  nnnOOOO    PPPp ...        Q
    AAAAA     BBBBB      CCCC      .....                DDD   EEEEE          FFFff   ....    GGGG         HHHHhh     II....     j  .  .
    AAAaa..   BBBBbb  CccDDDDD       ....               EEE   .F   GgghhhII  Jj KKKK       ...    ...     LLll  ...   MMMM     N   OooP
    ....  Aa  ..BCCC      .....            DDD          EEEe  FFf  .....         GGGG       HIIIIIii          . JJ   ....  KKk     LL
    AAAAAa  bbC.....      DDDDD            ....          eeFFFFff  GGGGG         ...    hh IIJJJ        KKK     L   MMMMMmmNNNN
    ..aBBB    CCCCc   .....        .....                ...   D.   E     FFFFFff   ggHHhiiiJKKKk     LLLLL       mmmNNNOP  Q   RRR
    AA BbCCCC   DD    Ee FFFFFff     GGGGG                 HH IIIi       JjjK..  LLLll     MMMMmm    ....       .   NNNOOOOOoo        P
    AB CCCCC    .....        ddEEEE     fffGgg   HHHHHhh      II jjKKKK         LLLL       MMMM    nn..   OO    PPPPPpp QQQQQqq
    AAA  BBB   CCCC      DDdd  EE  FFF        gggHh IIIii   JJJJ         K  LLLLl    MMm   NNOOOO         .   PP    .QQQRRRRR

from heapq import merge
from itertools import groupby, cycle, chain
from collections import defaultdict
from operator import attrgetter
from string import ascii_uppercase

# events are processed in this order:
# increasing start time, displacements (duration=0) first, and grouped by row_id
ev_sort_attrs = attrgetter("time", "duration", "row_id")


class Event:

    def __init__(self, duration, displacement=0, visible=True, time=None, row_id=None):
        self.duration = duration
        self.displacement = displacement
        self.visible = visible
        self.time = time
        self.row_id = row_id
        self.pos = None

    def draw(self, char):
        return char * self.duration + char.lower() * self.displacement

    def __lt__(self, other):
        return ev_sort_attrs(self) < ev_sort_attrs(other)


def Gap(duration):
    return Event(duration, visible=False)


class Timetable(list):
    def __init__(self, *args):
        """ compute positions for a list of rows of events """
        list.__init__(self, *args)

        # compute times for the events, and give them row_ids
        for i, row in enumerate(self):
            t = 0
            for ev in row:
                ev.time = t
                t += ev.duration
                ev.row_id = i

        # map times to position for displacements and event
        t2pos_disp = defaultdict(int) # maps times to position of synchronized start of displacements
        t2pos_ev = defaultdict(int) # maps times to position of synchronized start of events and gaps

        # the real work is done in the following loop
        t_prev = 0
        for t, g in groupby(merge(*self), key=attrgetter("time")):

            # different times should have a minimum distance corresponding to their difference
            t2pos_ev[t] = t2pos_disp[t] = max(t2pos_ev[t], t2pos_ev[t_prev] + t - t_prev)
            t_prev = t

            for (duration, row_id), g_row in groupby(g, key=attrgetter("duration", "row_id")): # process all displacements first, then the events
                pos_ev = t2pos_ev[t] if duration > 0 else t2pos_disp[t] # events and displacements start at different
                for ev in g_row:
                    ev.pos = pos_ev
                    pos_ev += ev.duration + ev.displacement
                t2pos_ev[t + ev.duration] = max(t2pos_ev[t + ev.duration], pos_ev)

        # keep our results...
        self.t2pos_ev = t2pos_ev
        self.t2pos_disp = t2pos_disp


    @staticmethod
    def str_row(row):
        """ draw row, uppercase letters for real events, lower case letters for
        displacements, dots for gaps"""

        ev_chars = cycle(ascii_uppercase)
        out = []
        l = 0
        for ev in row:
            if ev.pos > l:
                out.append(" " * (ev.pos - l))
            out.append(ev.draw(next(ev_chars) if ev.visible else "."))
            l = ev.pos + len(out[-1])
        return "".join(out)

    def __str__(self):
        max_t, max_p = max(self.t2pos_ev.items())
        w = len(str(max_t))
        header_temp = [" " * w] * (max_p + 1)
        for t, p in self.t2pos_ev.items():
            header_temp[p] = "%*d" % (w, t)
        headers = ("".join(header) for header in zip(*header_temp))

        rows = (self.str_row(row) for row in self)

        return "\n".join(chain(headers, rows))


if __name__ == "__main__":
    # original example
    row_one = [Event(1), Event(0,1), Event(1), Gap(1), Event(1), Gap(1), Event(0,1), Event(1), Event(1)]
    row_two = [Event(1), Event(1), Gap(1), Event(1, 1), Event(1), Event(1), Event(1)]
    row_thr = [Event(1), Event(1), Event(1), Event(1), Event(1), Event(0,1), Event(0,1), Event(1), Event(1)]

    timetable = Timetable([row_one, row_two, row_thr])
    print(timetable)

    print("-" * 80)

    # short example, shows ending times are not synchronized
    print(Timetable([[Event(2, 1)], [Event(1, 1), Event(1)], [Event(1, 2), Event(1)]]))

    print("-" * 80)

    # larger random example
    def random_row(l):
        import random
        res = []
        t = 0
        while t < l:
            x = random.random()
            if x < 0.1: res.append(Event(0, random.randint(1, 3)))
            elif x < 0.8: res.append(Event(min(random.randint(1, 5), l - t), random.randint(0, 1) * random.randint(0, 2)))
            else: res.append(Gap(min(random.randint(1, 5), l - t)))
            t += res[-1].duration
        return res

    print(Timetable([random_row(50) for _ in range(15)]))

关于python - 从消耗时间的项目和不消耗时间但仍需要绘制空间的项目生成基于时间线的线性表示，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/8439763/