我想向服务器发送一个文件和一些变量,以使用 AsyncTask 将其插入到 Android 应用程序的表格中。这是我的 Java 代码:
try {
URL url = new URL(upLoadServerUri);
HttpURLConnection httpURLConnection = (HttpURLConnection) url.openConnection();
httpURLConnection.setRequestMethod("POST");
httpURLConnection.setDoOutput(true);
httpURLConnection.setDoInput(true);
httpURLConnection.setUseCaches(false);
OutputStream outputStream = httpURLConnection.getOutputStream();
BufferedWriter bufferedWriter = new BufferedWriter(new OutputStreamWriter(outputStream,"UTF-8"));
String post_data= URLEncoder.encode("username" , "UTF-8")+"="+URLEncoder.encode(username,"UTF-8");
bufferedWriter.write(post_data);
bufferedWriter.flush();
bufferedWriter.close();
outputStream.close();
InputStream inputStream = httpURLConnection.getInputStream();
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(inputStream, "iso-8859-1"));
result="";
String line="";
while ((line=bufferedReader.readLine()) != null){
result += line;
}
bufferedReader.close();
inputStream.close();
httpURLConnection.disconnect();
}catch (MalformedURLException e){
e.printStackTrace();
}catch (IOException e){
e.printStackTrace();
}
try {
FileInputStream fileInputStream = new FileInputStream(sourceFile);
URL url = new URL(upLoadServerUri);
// Open a HTTP connection to the URL
conn = (HttpURLConnection) url.openConnection();
conn.setDoInput(true); // Allow Inputs
conn.setDoOutput(true); // Allow Outputs
conn.setUseCaches(false); // Don't use a Cached Copy
conn.setRequestMethod("POST");
conn.setRequestProperty("Connection", "Keep-Alive");
conn.setRequestProperty("ENCTYPE",
"multipart/form-data");
conn.setRequestProperty("Content-Type",
"multipart/form-data;boundary=" + boundary);
conn.setRequestProperty("bill", sourceFileUri);
dos = new DataOutputStream(conn.getOutputStream());
dos.writeBytes(twoHyphens + boundary + lineEnd);
dos.writeBytes("Content-Disposition: form-data; name=\"bill\";filename=\""
+ sourceFileUri + "\"" + lineEnd);
dos.writeBytes(lineEnd);
// create a buffer of maximum size
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
buffer = new byte[bufferSize];
// read file and write it into form...
bytesRead = fileInputStream.read(buffer, 0, bufferSize);
while (bytesRead > 0) {
dos.write(buffer, 0, bufferSize);
bytesAvailable = fileInputStream.available();
bufferSize = Math.min(bytesAvailable, maxBufferSize);
bytesRead = fileInputStream.read(buffer, 0,
bufferSize);
}
// send multipart form data necesssary after file
// data...
dos.writeBytes(lineEnd);
dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);
// Responses from the server (code and message)
serverResponseCode = conn.getResponseCode();
String serverResponseMessage = conn
.getResponseMessage();
// close the streams //
fileInputStream.close();
dos.flush();
dos.close();
return result;
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
和PHP代码:
if (is_uploaded_file($_FILES['bill']['tmp_name'])) {
$uploads_dir = './sensorLog/$user_name';
$tmp_name = $_FILES['bill']['tmp_name'];
$pic_name = $_FILES['bill']['name'];
move_uploaded_file($tmp_name, $uploads_dir.$pic_name);
if($conn->query($mysql_qry) === TRUE) {
echo "upload and update successful";
}else { echo "Error" . $mysql_qry . "<br>" . $conn->error;}
}else{ echo "File not uploaded successfully."; }
我使用了两个 httpconnection 对象,我认为这是问题所在。如何同时发送变量和文件?此代码将文件上传到服务器,但表未更新。它只是添加一个空行:(。
最佳答案
使用此类发送多部分请求:
class MultipartUtility {
public HttpURLConnection httpConn;
public OutputStream request;//if you wanna send anything out of ordinary use this;
private final String boundary = "*****";//alter this as you wish
private final String crlf = "\r\n";
private final String twoHyphens = "--";
public MultipartUtility(String requestURL)
throws IOException {
URL url = new URL(requestURL);
httpConn = (HttpURLConnection) url.openConnection();
httpConn.setUseCaches(false);
httpConn.setDoOutput(true);
httpConn.setDoInput(true);
httpConn.setRequestMethod("POST");
//alter this part if you wanna set any headers or something
httpConn.setRequestProperty("Connection", "Keep-Alive");
httpConn.setRequestProperty("Cache-Control", "no-cache");
httpConn.setRequestProperty(
"Content-Type", "multipart/form-data;boundary=" + this.boundary);
request = httpConn.getOutputStream();
}
//or add some other constructor to better fit your needs; like set cookies and stuff
public void addFormField(String name, String value)throws IOException {
request.write(( this.twoHyphens + this.boundary + this.crlf).getBytes());
request.write(("Content-Disposition: form-data; name=\"" + name + "\""+ this.crlf).getBytes());
request.write(this.crlf.getBytes());
request.write((value).getBytes());
request.write(this.crlf.getBytes());
request.flush();
}
public void addFilePart(String fieldName, File uploadFile)
throws IOException,Exception {
if(uploadFile.isDirectory())throw new Exception("for real? what do you expect to happen?");
request.write((this.twoHyphens + this.boundary + this.crlf).getBytes());
request.write(("Content-Disposition: form-data; name=\"" +
fieldName + "\";filename=\"" +
uploadFile.getName()+ "\"" + this.crlf).getBytes());
request.write(this.crlf.getBytes());
InputStream is=new FileInputStream(uploadFile);
byte[] bytes = new byte[1024];
int c=is.read(bytes);
while(c>0){
request.write(bytes,0,c);
c=is.read(bytes);
}
request.write(this.crlf.getBytes());
request.flush();
is.close();
}
public String finish() throws IOException {
String response ="";
request.write((this.twoHyphens + this.boundary +
this.twoHyphens + this.crlf).getBytes());
request.flush();
request.close();
int status = httpConn.getResponseCode();
if (status == HttpURLConnection.HTTP_OK) {
InputStream responseStream = httpConn.getInputStream();
byte[] b=new byte[1024];
int c=responseStream.read(b);
while(c>0){
response=response+new String(b,0,c);
c=responseStream.read(b);
}
responseStream.close();
} else {
httpConn.disconnect();
throw new IOException("Server returned non-OK status: " + status);
}
httpConn.disconnect();
return response;
}
public InputStream finish_with_inputstream()throws Exception{
request.write((this.twoHyphens + this.boundary +
this.twoHyphens + this.crlf).getBytes());
request.flush();
request.close();
int status = httpConn.getResponseCode();
if (status == HttpURLConnection.HTTP_OK) {
return httpConn.getInputStream();
} else {
throw new IOException("Server returned non-OK status: " + status);
}
}
}
例子:
try{
MultipartUtility m=new MultipartUtility("https://mydomain");//now add you different data parts;
m.addFilePart("file_part",new File("some_file_location"));
m.addFormField("value_name","value");
//call either of the below methods based on what you need; do not call both!
String result=m.finish();//call this if the response is a small text
InputStream is=m.finish_with_inputstream(); //call this if the response is huge and not fitting in memory; don't forget to disconnect the connection afterwards;
} catch (IOException e) {
e.printStackTrace();
}
现在您可以在 php 端的一个请求中处理所有这些数据:
$value=$_POST["value_name"];
$file_data=file_get_contents($_FILES["file_part"]["tmp_name"])
所以对于你的情况,它会像下面这样:
try{
MultipartUtility m=new MultipartUtility("https://mydomain");
m.addFilePart("bill",new File(sourceFile));
m.addFormField(URLEncoder.encode("username" , "UTF-8"),URLEncoder.encode(username,"UTF-8"));
String result=m.finish();
} catch (Exception e) {
e.printStackTrace();
}
关于java - 如何在 Android 中通过 http 协议(protocol)将多个文件和文本同时发送到服务器?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/54731371/
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