我有 2 个表(用户和信息)。 我需要选择所有用户数据和相关的最后插入的“信息文本”(插入时间)

表用户

+----+--------+----------+
| id | name   | adress   |
+----+--------+----------+
|  1 | Name 1 | Adress 1 |
|  2 | Name 2 | Adress 2 |
|  3 | user 3 | adress 3 |
|  4 | user 4 | adress 4 |
+----+--------+----------+

表格信息

+----+---------+----------+---------------------+
| id | id_user | infotext | insert_time         |
+----+---------+----------+---------------------+
|  1 |       1 | info 1   | 2016-11-24 14:03:23 |
|  2 |       1 | info 2.  | 2016-11-24 14:08:30 |
|  3 |       3 | text 3.  | 2016-11-24 14:08:46 |
+----+---------+----------+---------------------+

我当前的查询是:

SELECT  a.*, b.infotext FROM    user a LEFT JOIN infos b
            ON a.id = b.id_user
        LEFT JOIN
        (
            SELECT      id_user, MAX(insert_time) newestInsert
            FROM        infos
            GROUP BY    id_user
        ) c ON  c.id_user = b.id_user AND
                c.newestInsert = b.insert_time

但问题是它输出的 id 不明显:

+----+--------+----------+----------+
| id | name   | adress   | infotext |
+----+--------+----------+----------+
|  1 | Name 1 | Adress 1 | info 1   |
|  1 | Name 1 | Adress 1 | info 2.  |
|  3 | user 3 | adress 3 | text 3.  |
|  2 | Name 2 | Adress 2 | NULL     |
|  4 | user 4 | adress 4 | NULL     |
+----+--------+----------+----------+

我需要的最终结果是:

+----+--------+----------+----------+
| id | name   | adress   | infotext |
+----+--------+----------+----------+
|  1 | Name 1 | Adress 1 | info 2.  |
|  3 | user 3 | adress 3 | text 3.  |
|  2 | Name 2 | Adress 2 | NULL     |
|  4 | user 4 | adress 4 | NULL     |
+----+--------+----------+----------+

最佳答案

将第二个条件放在on 子句中。此方法将其作为相关子查询执行:

SELECT  u.*, i.infotext
FROM user u LEFT JOIN
     infos i
     ON u.id = i.id_user and
        i.insert_time = (SELECT MAX(i2.insert_time)
                         FROM infos i2
                         WHERE i2.id_user = i.id_user
                        );

关于MySql Left Join with subselect，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/40788108/