我从这里举了一个在 Android 中使用 SQLite 的例子:http://www.cnblogs.com/pangblog/p/3327696.html

而且我很难通过名字获得联系方式。如何更改 GetContact 函数以按名称搜索？

数据库处理程序:

public class DatabaseHandler extends SQLiteOpenHelper {

    //Database Version 
    private static final int DATABASE_VERSION = 1;

    //Database Name
    private static final String DATABASE_NAME = "contactsManager";

    //Contacts table name 
    private static final String TABLE_CONTACTS = "contacts";

    //Contacts Table Columns names 
    private static final String KEY_ID = "id";
    private static final String KEY_NAME = "name";
    private static final String KEY_PH_NUM = "phone_number";

    public DatabaseHandler(Context context) {
        super(context, DATABASE_NAME, null, DATABASE_VERSION);
    }

    // Creating Tables : CREATE TABLE table_name (column_name column_type);
    @Override
    public void onCreate(SQLiteDatabase db) {
        String CREATE_CONTACTS_TABLE = "CREATE TABLE " + TABLE_CONTACTS + "("
                + KEY_ID + " INTEGER PRIMARY KEY," + KEY_NAME + " TEXT,"
                + KEY_PH_NUM + " TEXT" + ")";       
        db.execSQL(CREATE_CONTACTS_TABLE);
    }

    // Upgrading database
    @Override
    public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {
        // Drop older table if existed 
        db.execSQL("DROP TABLE IF EXISTS " + TABLE_CONTACTS);

        // Create tables again
        onCreate(db);
    }   


    //Adding new contact 
    void addContact(Contact contact) {
        SQLiteDatabase db = this.getWritableDatabase();

        ContentValues values = new ContentValues();
        values.put(KEY_NAME, contact.getName()); // Contact Name
        values.put(KEY_PH_NUM, contact.getPhoneNumber()); // Contact Phone

        // Inserting Row
        db.insert(TABLE_CONTACTS, null, values);
        db.close(); // Closing database connection
    }

    // Getting single contact 
    Contact getContact(int id) {
        SQLiteDatabase db = this.getReadableDatabase();

        Cursor cursor = db.query(TABLE_CONTACTS, new String[] { KEY_ID,
                KEY_NAME, KEY_PH_NUM }, KEY_ID + "=?",
                new String[] { String.valueOf(id) }, null, null, null, null);
        if (cursor != null)
            cursor.moveToFirst();

        Contact contact = new Contact(Integer.parseInt(cursor.getString(0)),
                cursor.getString(1), cursor.getString(2));

        return contact;
    }

    // Getting All Contacts
    public List<Contact> getAllContacts() {
        List<Contact> contactList = new ArrayList<Contact>();
        // Select All Query ：SELECT * FROM tableName WHERE criteria
        String selectQuery = "SELECT  * FROM " + TABLE_CONTACTS;

        SQLiteDatabase db = this.getWritableDatabase();
        Cursor cursor = db.rawQuery(selectQuery, null);

        // looping through all rows and adding to list
        if (cursor.moveToFirst()) {
            do {
                Contact contact = new Contact();
                contact.setID(Integer.parseInt(cursor.getString(0)));
                contact.setName(cursor.getString(1));
                contact.setPhoneNumber(cursor.getString(2));
                // Adding contact to list
                contactList.add(contact);
            } while (cursor.moveToNext());
        }

        return contactList;
    }


}

联系方式:

public class Contact {

    int _id;
    String _name;
    String _phone_number;


    public Contact() {

    }


    public Contact(int id, String name, String phone_number) {
        this._id = id;
        this._name = name;
        this._phone_number = phone_number;
    }


    public Contact(String name, String phone_number) {
        this._name = name;
        this._phone_number = phone_number;
    }

    public int getID() {
        return this._id;
    }

    public void setID(int id) {
        this._id = id;
    }

    public String getName() {
        return this._name;
    }

    public void setName(String name) {
        this._name = name;
    }

    public String getPhoneNumber() {
        return this._phone_number;
    }

    public void setPhoneNumber(String phone_number) {
        this._phone_number = phone_number;
    }


}

最佳答案

getContact 中数据库查询中的 where 子句当前为 id = ? 并且 ? 已替换为 id 参数。要按名称搜索，您需要做的是修改该部分。

// Getting single contact 
Contact getContact(String name) {
    SQLiteDatabase db = this.getReadableDatabase();

    Cursor cursor = db.query(TABLE_CONTACTS, new String[] { KEY_ID,
            KEY_NAME, KEY_PH_NUM }, KEY_NAME + "=?",
            new String[] { name }, null, null, null, null);
    //...

您还应该稍微更改“工作”代码，因为它不是很安全。游标不能为 null(实际上)，但是如果数据库中没有这样的名称，cursor.moveToFirst() 可能/将会失败。如果失败，您将在 cursor.getString(0) 处收到异常，因为游标没有可从中获取数据的行。

删除 null 检查，并检查光标是否可以移动到第一个位置(不为空)。您还应该在不再需要时关闭光标。

Contact contact = null;
if (cursor.moveToFirst()) {
    contact = new Contact(Integer.parseInt(cursor.getString(0)),
            cursor.getString(1), cursor.getString(2));
}
cursor.close();
// can return null if no contact was found.
return contact;

关于Android SQLite 按名称搜索，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/18868712/