我有 div container里面有列表(卡片)。当我将它悬停时，卡片开始移动(translateX animation)。 container的width是 300px , 元素计入 container:3 , 每个元素 width:100px .

所以你可以一起看到容器中的 3 个元素 overflow:hidden .我想做什么？，是当没有元素显示时 translateX 动画 -100px = 100px 第三个元素后的空格，它从列表中的 1 个元素开始，紧随其后，没有空格。

目前，我不知道如何在没有重复等的情况下完成它。

这是我目前所拥有的:
Fiddle (悬停卡片看翻译动画)

更新 1:
以代码和数据(卡片数量，容器大小)为例，我将尝试更好地解释我想要的内容:我的目标是建立卡片列表，按下按钮后，列表将开始移动(如示例使用 translateX 动画)一段时间(例如 translateX: 12491px ，动画持续时间: 15s ;)然后停止。但问题是列表中的 crad 数量将在 3-40 张卡片的范围内(每张卡片的宽度和高度为 100 像素)。所以，当我设置 translateX: 12491像素例如，它将超出范围，并且在列表中的最后一张卡片之后会出现空白。我希望第一张和最后一张卡以某种方式绑定(bind)，并且在最后一张卡立即出现在列表中的第一张卡等之后。也许我正在以错误的方式寻找解决方案，但我想你理解主要思想。

更新 2:
我发现 cs:go 使用了我想在 html\css\js 上编写的动画。这是视频:youtube.com

html:

<div class="container">
    <div class="cards">
        <div class="card">
        1
    </div>
    <div class="card">
        2
    </div>
    <div class="card">
        3
    </div>
    </div>
</div>

.container
{
    width:300px;
        height: 100px;
    border: 2px solid black;
    overflow: hidden;
}
.card
{
    float:left;
    height: 100px;
    width: 100px;
    background-color:blue;
    box-sizing: border-box;
    border: 2px solid red;
    color: white;
    font-size: 23px;
}
.cards:hover
{
    transform: translateX(-100px);
    transition-duration: 3s;
    animation-duration: 3s;
    animation-fill-mode: forwards;
}

最佳答案

start from 1 elements in the list immediately after last, with no blank space

I have no idea how it could be done without duplicates

var list = document.querySelector('.cardList'), // cache the container
    cards = document.querySelectorAll('.card'), // cache the list of cards
    start = document.getElementById('start'),   // buttons
    stop = document.getElementById('stop'), 
    reset = document.getElementById('reset'), 
    raf, init = 0, counter = 0, lastCard, currentIteration = 0, // general purpose variables
    settings = { // settings object to help make things configurable
        'width': 100, 'height': 100, 'speed': 2, 
        'iterations': 2, 'count': cards.length 
    }
;
start.addEventListener('click', startClick); // wire up click event on buttons
stop.addEventListener('click', stopClick);
reset.addEventListener('click', resetClick);
initialize(); // initialize to arrange the cards at start

function initialize() {
    // loop thru all cards and set the left property as per width and index position
    [].forEach.call(cards, function(elem, idx) { 
        elem.style.left = (settings.width * idx) + 'px';
    }); 
    init = -(settings.width); // initialize the view cutoff
    lastCard = cards[settings.count - 1]; // identify the last card
    counter = 0; currentIteration = 0; // reset some counters
    settings.speed = +(document.getElementById('speed').value);
    settings.iterations = +(document.getElementById('iter').value);
}
function startClick() { 
    initialize(); raf = window.requestAnimationFrame(keyframes); // start animating
}
function stopClick() { window.cancelAnimationFrame(raf); } // stop animating
function resetClick() { // stop animating and re-initialize cards to start again
    window.cancelAnimationFrame(raf); 
    document.getElementById('speed').value = '2';
    document.getElementById('iter').value = '2';
    initialize(); 
}

// actual animation function
function keyframes() {
    var currentCard, currentLeft = 0, newLeft = 0;
    // iterate all cards and decrease the left property based on speed
    [].forEach.call(cards, function(elem, idx) {
        elem.style.left = (parseInt(elem.style.left) - settings.speed) + 'px';
    }); 
    currentCard = cards[counter]; // identify left-most card
    currentLeft = parseInt(currentCard.style.left); // get its left position
    if (currentLeft <= init) { // check if it has gone out of view
        // calculate position of last card
        newLeft = parseInt(lastCard.style.left) + settings.width;
        list.appendChild(currentCard); // move the card to end of list
        currentCard.style.left = newLeft + 'px'; // change left position based on last card
        lastCard = currentCard; // set this as the last card for next iteration
        counter = (counter + 1) % settings.count; // set the next card index
        if ((settings.iterations > 0) && (counter >= (settings.count - 1))) { 
            currentIteration++; // check settings for repeat iterations
        }
    }
    if (currentIteration >= settings.iterations) { return; } // when to stop
    raf = window.requestAnimationFrame(keyframes); // request another animation frame
};

* { box-sizing: border-box; padding: 0; margin: 0; }
.cardList { 
    position: relative; height: 100px; width: 300px; 
    margin: 10px; border: 2px solid #33e; 
    overflow: hidden; white-space: nowrap; 
}
.card { 
    position: absolute; left: 0; top: 0; text-align: center;
    height: 100px; width: 100px; line-height: 100px;
    background-color: #99e; 
    font-family: monospace; font-size: 2em; color: #444;
    border-left: 1px solid #33e; border-right: 1px solid #33e;
}

div.controls, button { margin: 10px; padding: 8px; font-family: monospace; }
div.controls input { width: 48px; padding: 2px; text-align: center; font-family: monospace; }

<div class="controls">
    <label>Speed <input id="speed" type="number" min="1" max="8" value="2" />x</label>
    &nbsp;|&nbsp;
    <label>Iterations <input id="iter" type="number" min="0" max="8" value="2" /></label>
</div>
<div class="cardList">
    <div class="card">1</div>
    <div class="card">2</div>
    <div class="card">3</div>
    <div class="card">4</div>
</div>
<button id="start">Start</button>
<button id="stop">Stop</button>
<button id="reset">Reset</button>

var $cardList 	= $('.cardList').first(), 
    $cards 		= $('.card'), 
    $speed 		= $('input[name=speed]'), 
    width 		= 100, 
    randomize 	= true, 
    distance 	= 20 * width 
;

for (var i = 0; i < 50; i++) {
    $cards.clone().appendTo($cardList);
}

function spin() {
    var newMargin = 0, newDistance = distance, 
        speed = +($speed.filter(':checked').val());
    if (randomize) {
        newDistance = Math.floor(Math.random() * $cards.length * 5);
		newDistance += $cards.length * 5;
        newDistance *= width;
    } 
	newMargin = -(newDistance);
    $cards.first().animate({
        marginLeft: newMargin
    }, speed);
}

$('#spin').click(function() {
    $cards.first().css('margin-left', 0);
    spin();
    return false;
});

* { box-sizing: border-box; padding: 0; margin: 0; }
.cardList { 
    height: 100px; width: 302px; position: relative;
    margin: 10px; border: 1px solid #33e; 
    overflow: hidden; white-space: nowrap; 
}
.card { 
    display: inline-block; text-align: center;
    height: 100px; width: 100px; line-height: 100px;
    background-color: #99e; 
    font-family: monospace; font-size: 2em; color: #444;
    border-left: 1px solid #33e; border-right: 1px solid #33e;
}
.cardList::before, .cardList::after {
    content: ''; display: block; z-index: 100;
    width: 0px; height: 0px; transform: translateX(-50%);
	border-left: 8px solid transparent;
	border-right: 8px solid transparent;    
}
.cardList::before {
    position: absolute; top: 0px; left: 50%;
	border-top: 12px solid #33e;
}
.cardList::after {
    position: absolute; bottom: 0px; left: 50%;
	border-bottom: 12px solid #33e;
}
div.controls, button { margin: 10px; padding: 8px; font-family: monospace; }
div.controls input { width: 48px; padding: 2px; text-align: center; font-family: monospace; }

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="controls">
    <label>Speed: </label>
    &nbsp;|&nbsp;
    <label><input name="speed" type="radio" value='6000' />Slow</label>
    <label><input name="speed" type="radio" value='5000' checked />Medium</label>
    <label><input name="speed" type="radio" value='3000' />Fast</label>
</div>
<div class="cardList"><!--
    --><div class="card">1</div><!--
    --><div class="card">2</div><!--
    --><div class="card">3</div><!--
    --><div class="card">4</div><!--
--></div>
<button id="spin">Spin</button>

关于javascript - 具有有限元素的列表轮换，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/33412192/