我有这样一个 xml:

<?xml version="1.0" encoding="UTF-8"?>
<workflow>
    <call name="api1">
        <repeat>100</repeat>
        <delay>60</delay>
        <call name="apicallafterapi1">
            <fields>c_id</fields>
            <repeat>10</repeat>
            <delay>2</delay>
        </call>    
    </call>

    <call name="api2">
        <repeat>1000</repeat>
        <delay>5</delay>
    </call>
    <call name="api3">
        <repeat>1000</repeat>
    </call>
</workflow>  

call 复杂元素可以存在于另一个 call 元素中，例如 api1。这个 xml 结构有效吗？如果是这样，我如何使用 SAX

class Call {
    String name;
    int repeat;
    int delay;
    List<Call> onResponseCall = new ArrayList<>();

    public void setName(String name) {
        this.name = name;
    }
    public void setRepeat(int repeat) {
        this.repeat = repeat;
    }
    public void setDelay(int delay) {
        this.delay = delay;
    }
    public void addCall(Call c) {
        onResponseCall.add(c);
    }

}
class WorkFlow {
    private List<Call> calls = new ArrayList<>();

    public void addCall(Call c) {
        calls.add(c);
    }
}

@Override
public void characters(char[] buffer, int start, int length) {
    temp = new String(buffer, start, length);
}

@Override
public void startElement(String uri, String localName, String qName, Attributes attributes) throws SAXException {
    temp = "";
    if (qName.equalsIgnoreCase("call")) {
        call = new Call();
        call.setName(attributes.getValue("name"));
    }
}

@Override
public void endElement(String uri, String localName, String qName) throws SAXException {
    if (qName.equalsIgnoreCase("call")) {
        // add it to the list
        workflow.add(call);

    } else if (qName.equalsIgnoreCase("repeat")) {
        call.setRepeat(Integer.parseInt(temp));
    } else if (qName.equalsIgnoreCase("delay")) {
        call.setDelay(Integer.parseInt(temp));
    } else if (qName.equalsIgnoreCase("call")) {
        Call c = new Call();
    }

}  

我应该在哪里调用 Workflow.add(call) & Call.add(call)

编辑

<call>
        <name>send_message</name>
        <repeat>1</repeat>
        <delay>2</delay>
        <useParentFields>
            <field>c_id</field>
            <field>m_id</field>
        </useParentFields>
        <uniqueFields>
            <field type="Long.class">d_id</field>
            <field type="Long.class">a_id</field>
        </uniqueFields>
    </call> 

最佳答案

我很感兴趣如何去做，解决方案似乎很简单。要使用核心解决方案，您可以查看我的 commit .

如果您只需要核心答案，请检查下面的代码:

工作流程

import java.util.List;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement(name = "workflow")
public class Workflow {
    @XmlElement(name="call")
    private List<Call> calls;
}

import java.util.List;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlAttribute;
import javax.xml.bind.annotation.XmlElement;

调用

@XmlAccessorType(XmlAccessType.FIELD)
public class Call {

    @XmlAttribute
    private String name;
    private String repeat;
    private String delay;
    private String fields;
    @XmlElement(name="call")
    private List<Call> call;

}

例如输入点

import java.io.File;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Marshaller;
import javax.xml.bind.Unmarshaller;

public class Main {
    public static void main(String[] args) throws JAXBException {
        JAXBContext jc = JAXBContext.newInstance(Workflow.class);

        Unmarshaller unmarshaller = jc.createUnmarshaller();
        File xml = new File("src/variant.xml");
        Workflow sc = (Workflow) unmarshaller.unmarshal(xml);

        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.setProperty(Marshaller.JAXB_SCHEMA_LOCATION, "Workflow.xml");
        marshaller.marshal(sc, System.out);

    }
}

variant.xml - 你的 xml

<?xml version="1.0" encoding="UTF-8"?>
<workflow>
    <call name="api1">
        <repeat>100</repeat>
        <delay>60</delay>
        <call name="apicallafterapi1">
            <fields>c_id</fields>
            <repeat>10</repeat>
            <delay>2</delay>
        </call>
    </call>

    <call name="api2">
        <repeat>1000</repeat>
        <delay>5</delay>
    </call>
    <call name="api3">
        <repeat>1000</repeat>
    </call>
</workflow>

我希望通过共享示例可以清楚地了解它，但无论如何，如果有任何问题，请提出。

我认为如果 xml 已经解析，您可以处理名称比较。

为了使对象更有用，您可以添加 getter\setter\equals\hashCode 等等...

关于java - 如何解析带有与父元素同名的子元素的xml，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/45199165/