我试图在我的数据库中调用 Terminal_GetTicket 存储过程，但不断收到以下异常:

PropertyReferenceException: No property getTicket found for type TicketInfo

我已经使用一个非常简单的测试实体对我的配置进行了交叉验证，一切似乎都工作正常，但对于实际情况，有些地方出了问题。

这是我的域实体(TicketInfo):

@Entity
@NamedStoredProcedureQuery(name = "TicketInfo.getTicket", procedureName = "Terminal_GetTicket", resultClasses = TicketInfo.class, parameters = { 
    @StoredProcedureParameter(mode = ParameterMode.IN, name = "sys_id_game", type = Integer.class)})
public class TicketInfo {

    @Id @GeneratedValue
    private Long id;
    private String idTicket;
    private Integer externalTicketCode;
    private Short sequenseAlert;
    private Integer dlTimeStamp;

所有实例变量都正确定义了它们的 getter 和 setter，存储过程总共有 5 个输出参数匹配 TicketInfo 的属性。

此外，这是我的存储库界面:

public interface TicketInfoRepository extends CrudRepository<TicketInfo, Long> {
    @Transactional(timeout = 5)
    @Procedure
    TicketInfo getTicket(Integer sys_id_game);
}

此外，这是我的 context.xml 文件(用于 Spring):

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:jpa="http://www.springframework.org/schema/data/jpa"
    xmlns:context="http://www.springframework.org/schema/context"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns:repository="http://www.springframework.org/schema/data/repository"
    xsi:schemaLocation="http://www.springframework.org/schema/beans 
        http://www.springframework.org/schema/beans/spring-beans-4.0.xsd
        http://www.springframework.org/schema/context
        http://www.springframework.org/schema/context/spring-context-4.1.xsd
        http://www.springframework.org/schema/data/jpa 
        http://www.springframework.org/schema/data/jpa/spring-jpa-1.8.xsd
        http://www.springframework.org/schema/data/repository
        http://www.springframework.org/schema/data/repository/spring-repository-1.5.xsd">

    <context:component-scan base-package="ar.com.boldt.godzilla" />
    <jpa:repositories base-package="xx.xxx.xxx.godzilla.business.dao" />

    <bean id="jpaVendorAdapter"
        class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
        <property name="showSql" value="${dataSource.show.sql}" />
        <property name="generateDdl" value="false" />
        <property name="database" value="SQL_SERVER" />
    </bean>

    <bean id="entityManagerFactory"
        class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean">
        <property name="dataSource" ref="dataSource" />
        <property name="jpaVendorAdapter" ref="jpaVendorAdapter" />
        <!-- spring based scanning for entity classes -->
        <property name="packagesToScan" value="xx.xxx.xxx.godzilla.business.dao" />
    </bean>

    <bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager" />

    <bean id="cacheManager" class="org.springframework.cache.ehcache.EhCacheCacheManager">
        <property name="cacheManager" ref="ehcache" />
    </bean>

    <bean id="ehcache"
        class="org.springframework.cache.ehcache.EhCacheManagerFactoryBean">
        <property name="configLocation" value="classpath:ehcache.xml" />
    </bean>
</beans>

最后是存储过程本身的简化版本:

ALTER PROCEDURE [Terminal_GetTicket](
 @arg int 
,@res int output
,@res2 int output
)
as
Declare @error int

select 0, 1, 2

RETURN @error

现在，每当我尝试设置 @Autowired 注释时，我都会遇到上述异常。

最佳答案

我记得我一直在纠结于MS SQL存储过程和spring-data-jpa。这就是我成功运行它的方式:

型号:

@NamedNativeQueries({
    @NamedNativeQuery(
            name = "yourInternalName",
            query = "EXEC [procedure_name] :param1, :param2",
            resultClass = Foo.class
    )
 })
 @Entity
 public class Foo{

     /* Fields, getters, setters*/
}

这很简单。但是这种方法不同，您没有直接声明过程(这也是如果您决定更改 RDBS 则它不必工作的原因)。

然后你必须扩展你的存储库:

public interface FooRepositoryCustom {

     Foo fancyMethodName(arg1, arg2);
}

并直接实现它:

public class FooRepositoryImpl implements FooRepositoryCustom {


@PersistenceContext
EntityManager entityManager;

@Override
public Foo fancyMethodName(arg1, arg2) {

    Query query = entityManager.createNamedQuery("yourInternalName");
    query.setParameter("param1", arg1);
    query.setParameter("param2", arg2);
    return query.getResultList();
}

让我们把它们放在一起:

public interface FooRepository extends CrudRepository<Foo, Long>, FooRepositoryCustom {

}

请注意，如果您决定返回例如 Foo 对象的列表，您只能在自定义存储库中编辑返回值。

关于java - 如何使用 JPA 和 Spring Data 执行存储过程？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/29612550/