草庐IT

java - 如何在 javaFX/8 中摇动登录对话框

coder 2024-03-30 原文

当用户输入错误的登录名/密码对时,如何使我的 javaFX/8 对话框更优雅地摇晃?。

由于 java8u40 中的对话框没有,我打算自己制作一个。但是,它看起来还不够好。

这是怎么回事?有人可以帮忙吗?有更好的方法吗?


public void loginDialog() {
    // Create the custom dialog.
    Dialog<Pair<String, String>> dialog = new Dialog<>();
    dialog.setTitle("Mars Simulation Project");
    dialog.setHeaderText("Log in");
    dialog.setContentText("Enter your username and password : ");
    dialog.initModality(Modality.NONE);
    // Set the button types.
    ButtonType loginButtonType = new ButtonType("Login", ButtonData.OK_DONE);
    dialog.getDialogPane().getButtonTypes().addAll(loginButtonType, ButtonType.CANCEL);

    // Create the username and password labels and fields.
    GridPane grid = new GridPane();
    grid.setHgap(10);
    grid.setVgap(10);
    grid.setPadding(new Insets(20, 150, 10, 10));

    TextField tfPlayer = new TextField();
    tfPlayer.setPromptText("e.g. m03j");
    PasswordField tfPassword = new PasswordField();
    tfPassword.setPromptText("xxxx");

    Button defaultPWB = new Button("Use Default");
    Button guestB = new Button("As Guest");

    defaultPWB.setOnAction(event -> {
        tfPassword.setText("msp0");
    } );

    guestB.setOnAction(event -> {
        tfPlayer.setText("Guest_");
        tfPassword.setText("msp0");
    } );

    grid.add(new Label("Player Name :"), 0, 0);
    grid.add(tfPlayer, 1, 0);
    grid.add(guestB, 2, 0);
    grid.add(new Label("Password :"), 0, 1);
    grid.add(tfPassword, 1, 1);
    grid.add(defaultPWB, 2, 1);

    // Enable/Disable login button depending on whether a username was entered.
    Node loginButton = dialog.getDialogPane().lookupButton(loginButtonType);
    loginButton.setDisable(true);

    // Do some validation (using the Java 8 lambda syntax).
    tfPlayer.textProperty().addListener((observable, oldValue, newValue) -> {
        loginButton.setDisable(newValue.trim().isEmpty());
    } );

    dialog.getDialogPane().setContent(grid);

    // Request focus on the player name field by default.
    Platform.runLater(() -> tfPlayer.requestFocus());

    // Convert the result to a player name /host address pair when the login
    // button is clicked.
    dialog.setResultConverter(dialogButton -> {
        if (dialogButton == loginButtonType) {
            return new Pair<>(tfPlayer.getText(), tfPassword.getText());
        }
        return null;
    } );

    Optional<Pair<String, String>> result = dialog.showAndWait();

    result.ifPresent(input -> {
        playerName = tfPlayer.getText();
        logger.info("Player " + input.getKey() + " connecting to server at " + serverAddressStr);

        try {
            dialog.show();
            makeContact(serverAddressStr);
            // obtain a client id
            boolean isSuccessful = sendRegister();

            if (isSuccessful) {
                dialog.close();
                // establish chat...

            } else {
                // shake the dialog or send an alert to inform the user the
                // player name is NOT valid
                DialogEarthquakeCenter dec = new DialogEarthquakeCenter(dialog);
                dec.startTimer();

                try {
                    System.out.println("start sleeping ");
                    Thread.sleep(2000);
                    System.out.println("done sleeping ");
                }
                catch (InterruptedException e) {}

                loginDialog();
            }

        } catch (Exception e) {
            e.printStackTrace();
        }
    } );

到目前为止,我的问题是只要我点击“登录”按钮,对话框就会默认关闭。

因此我必须使用 dialog.show() 使其再次显示。

[edit] 然而,这仍然无法阻止瞬间间隙的发生(看到对话框消失并重新出现)。

之后,我创建了一个 DialogEarthquakeCenter 实例来摇动对话框。

请注意,我下面的 DialogEarthquakeCenter 是直接修改这个原始的:

https://github.com/gigiigig/Java-Chat/blob/master/tag/FacebookChatCore_Original/src/facebookchat/ui/common/DialogEarthquakeCenter.java

import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.Timer;
import javafx.animation.KeyFrame;
import javafx.animation.Timeline;
import javafx.application.Platform;
import javafx.scene.control.Dialog;
import javafx.util.Duration;
import javafx.util.Pair;

public class DialogEarthquakeCenter {

public static final int SHAKE_DISTANCE = 10;
public static final double SHAKE_CYCLE = 50;
public static final int SHAKE_DURATION = 500;
public static final int SHAKE_UPDATE = 5;

private Dialog<Pair<String, String>> dialog;
private int x, y;
private long startTime;
private Timer shakeTimer;
private final double TWO_PI = Math.PI * 2.0;
private Timeline timeline;

public DialogEarthquakeCenter(Dialog<Pair<String, String>> parent) {
    dialog = parent;
}

/**
 * Creates and starts the timer
 *
 * @return Scene
 */
public void startTimer() {
    x = (int) dialog.getX();
    y = (int) dialog.getY();
    startTime = System.currentTimeMillis();
    // Set up earth time text update
    timeline = new Timeline(new KeyFrame(Duration.millis(SHAKE_DURATION), ae -> startNudging()));
    //timeline.setCycleCount(javafx.animation.Animation.INDEFINITE);
    timeline.play();
}

public void startNudging() {
    x = (int) dialog.getX();
    y = (int) dialog.getY();
    startTime = System.currentTimeMillis();
    shakeTimer = new Timer(SHAKE_UPDATE, new ActionListener() {
        public void actionPerformed(ActionEvent e) {
            shake();
        }
    });

    shakeTimer.start();
}

public void shake() {
    // calculate elapsed time
    long elapsed = System.currentTimeMillis() - startTime;
    //System.out.println("elapsed is " + elapsed);
    // use sin to calculate an x-offset
    double waveOffset = (elapsed % SHAKE_CYCLE) / SHAKE_CYCLE;
    double angle = waveOffset * TWO_PI;
    // offset the x-location by an amount
    // proportional to the sine, up to shake_distance
    int shakenX = (int) ((Math.sin(angle) * SHAKE_DISTANCE) + x);

    Platform.runLater(() -> {
        //dialog.hide();
        dialog.setX(shakenX);
        //System.out.println("set shakenX to " + shakenX);
        dialog.setY(y);
        dialog.show();
    });

    //try {Thread.sleep(20);}
    //catch (InterruptedException ex) {}

    // should we stop timer
    if (elapsed >= SHAKE_DURATION) {
        stopShake();

    }
}

public void stopShake() {
    shakeTimer.stop();
    Platform.runLater(() -> {
        timeline.stop();
        dialog.close();
    });
}
}

我确实注意到 controlsfx 对话框有一个 shake() 方法。

有谁知道它是否有效?

参见 https://code.google.com/p/mqtt-spy/source/browse/mqtt-spy/src/main/java/org/controlsfx/dialog/CustomDialogs.java?r=6ec0240e4e64d1b8cc2b59bc77cd5902a68e0c81

非常感谢任何意见!

最佳答案

有一种方法可以在用户使用 Dialog API 单击登录按钮后,在窗口关闭之前添加一个转换。

使用 dialog.show() 而不是 dialog.showAndWait()`,诀窍就是捕获按钮上的点击操作,使用事件,然后执行所需的逻辑。

dialog.initModality(Modality.APPLICATION_MODAL);
dialog.show();            

loginButton.addEventFilter(EventType.ROOT, 
    e->{
        if(e.getEventType().equals(ActionEvent.ACTION)){                
            e.consume();
            // (hardcoded) Login Validation
            boolean isSuccessful = false;
            if (isSuccessful) {
                dialog.close();
            }
            else {
                // perform animation and close the dialog (or any other action)
                ShakeTransition anim = new ShakeTransition(dialog.getDialogPane(), t->dialog.close());
                anim.playFromStart();
            }
        }
    });

对于摇动动画,我修改了来自 Jasper 的 ShakeTransition Potts ,以便移动对话窗口,正如@jewelsea 已经指出的那样:

/**
 * Animate a shake effect on the given node
 * 
* Based on CachedTimelineTransition, a Transition that uses a Timeline internally 
* and turns SPEED caching on for the animated node during the animation.
* 
* https://github.com/fxexperience/code/blob/master/FXExperienceControls/src/com/fxexperience/javafx/animation/CachedTimelineTransition.java
* 
* and ShakeTransition
* 
* https://github.com/fxexperience/code/blob/master/FXExperienceControls/src/com/fxexperience/javafx/animation/ShakeTransition.java
* 
* @author Jasper Potts
*/
class ShakeTransition extends Transition {

    private final Interpolator WEB_EASE = Interpolator.SPLINE(0.25, 0.1, 0.25, 1);
    private final Timeline timeline;
    private final Node node;
    private boolean oldCache = false;
    private CacheHint oldCacheHint = CacheHint.DEFAULT;
    private final boolean useCache=true;
    private final double xIni;

    private final DoubleProperty x = new SimpleDoubleProperty();

    /**
    * Create new ShakeTransition
    * 
    * @param node The node to affect
    */
    public ShakeTransition(final Node node, EventHandler<ActionEvent> event) {
        this.node=node;
        statusProperty().addListener((ov, t, newStatus) -> {
           switch(newStatus) {
               case RUNNING:
                   starting();
                   break;
               default:
                   stopping();
                   break;
           }
        });

        this.timeline= new Timeline(
                new KeyFrame(Duration.millis(0), new KeyValue(x, 0, WEB_EASE)),
                new KeyFrame(Duration.millis(100), new KeyValue(x, -10, WEB_EASE)),
                new KeyFrame(Duration.millis(200), new KeyValue(x, 10, WEB_EASE)),
                new KeyFrame(Duration.millis(300), new KeyValue(x, -10, WEB_EASE)),
                new KeyFrame(Duration.millis(400), new KeyValue(x, 10, WEB_EASE)),
                new KeyFrame(Duration.millis(500), new KeyValue(x, -10, WEB_EASE)),
                new KeyFrame(Duration.millis(600), new KeyValue(x, 10, WEB_EASE)),
                new KeyFrame(Duration.millis(700), new KeyValue(x, -10, WEB_EASE)),
                new KeyFrame(Duration.millis(800), new KeyValue(x, 10, WEB_EASE)),
                new KeyFrame(Duration.millis(900), new KeyValue(x, -10, WEB_EASE)),
                new KeyFrame(Duration.millis(1000), new KeyValue(x, 0, WEB_EASE))
            );
        xIni=node.getScene().getWindow().getX();
        x.addListener((ob,n,n1)->(node.getScene().getWindow()).setX(xIni+n1.doubleValue()));

        setCycleDuration(Duration.seconds(1));
        setDelay(Duration.seconds(0.2));
        setOnFinished(event);
    } 

    /**
    * Called when the animation is starting
    */
    protected final void starting() {
        if (useCache) {
            oldCache = node.isCache();
            oldCacheHint = node.getCacheHint();
            node.setCache(true);
            node.setCacheHint(CacheHint.SPEED);
        }
    }

    /**
    * Called when the animation is stopping
    */
    protected final void stopping() {
        if (useCache) {
            node.setCache(oldCache);
            node.setCacheHint(oldCacheHint);
        }
    }

    @Override 
    protected void interpolate(double d) {
        timeline.playFrom(Duration.seconds(d));
        timeline.stop();
    }
}

这将是一个使用您的登录对话框的 JavaFX 应用程序:

@Override
public void start(Stage primaryStage) {
    Button btn = new Button();
    btn.setText("Show Login Dialog");
    btn.setOnAction(mevent -> {

        // Create the custom dialog.
        Dialog<Pair<String, String>> dialog = new Dialog<>();
        dialog.setTitle("Mars Simulation Project");
        dialog.setHeaderText("Log in");
        dialog.setContentText("Enter your username and password : ");
        dialog.initModality(Modality.NONE);
        // Set the button types.
        ButtonType loginButtonType = new ButtonType("Login", ButtonData.OK_DONE);
        dialog.getDialogPane().getButtonTypes().addAll(loginButtonType, ButtonType.CANCEL);

        // Create the username and password labels and fields.
        GridPane grid = new GridPane();
        grid.setHgap(10);
        grid.setVgap(10);
        grid.setPadding(new Insets(20, 150, 10, 10));

        TextField tfPlayer = new TextField();
        tfPlayer.setPromptText("e.g. m03j");
        PasswordField tfPassword = new PasswordField();
        tfPassword.setPromptText("xxxx");

        Button defaultPWB = new Button("Use Default");
        Button guestB = new Button("As Guest");
        defaultPWB.setOnAction(event -> {
            tfPassword.setText("msp0");
        } );

        guestB.setOnAction(event -> {
            tfPlayer.setText("Guest_");
            tfPassword.setText("msp0");
        } );

        grid.add(new Label("Player Name :"), 0, 0);
        grid.add(tfPlayer, 1, 0);
        grid.add(guestB, 2, 0);
        grid.add(new Label("Password :"), 0, 1);
        grid.add(tfPassword, 1, 1);
        grid.add(defaultPWB, 2, 1);

        // Enable/Disable login button depending on whether a username was entered.
        Node loginButton = dialog.getDialogPane().lookupButton(loginButtonType);
        loginButton.setDisable(true);

        // Do some validation (using the Java 8 lambda syntax).
        tfPlayer.textProperty().addListener((observable, oldValue, newValue) -> {
            loginButton.setDisable(newValue.trim().isEmpty());
        } );

        dialog.getDialogPane().setContent(grid);

        // Request focus on the player name field by default.
        Platform.runLater(() -> tfPlayer.requestFocus());

        dialog.initModality(Modality.APPLICATION_MODAL);
        dialog.show();            

        loginButton.addEventFilter(EventType.ROOT, 
            e->{
                if(e.getEventType().equals(ActionEvent.ACTION)){
                    e.consume();
                    // (hardcoded) Login Validation
                    boolean isSuccessful = false;
                    if (isSuccessful) {
                        dialog.close();
                    }
                    else {
                        ShakeTransition anim = new ShakeTransition(dialog.getDialogPane(), t->dialog.close());
                        anim.playFromStart();
                    }
                }
            });
    });

    StackPane root = new StackPane();
    root.getChildren().add(btn);

    Scene scene = new Scene(root, 300, 250);

    primaryStage.setTitle("Shaky Login Dialog");
    primaryStage.setScene(scene);
    primaryStage.show();
}

关于java - 如何在 javaFX/8 中摇动登录对话框,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29911552/

有关java - 如何在 javaFX/8 中摇动登录对话框的更多相关文章

  1. ruby - 如何在 Ruby 中顺序创建 PI - 2

    出于纯粹的兴趣,我很好奇如何按顺序创建PI,而不是在过程结果之后生成数字,而是让数字在过程本身生成时显示。如果是这种情况,那么数字可以自行产生,我可以对以前看到的数字实现垃圾收集,从而创建一个无限系列。结果只是在Pi系列之后每秒生成一个数字。这是我通过互联网筛选的结果:这是流行的计算机友好算法,类机器算法:defarccot(x,unity)xpow=unity/xn=1sign=1sum=0loopdoterm=xpow/nbreakifterm==0sum+=sign*(xpow/n)xpow/=x*xn+=2sign=-signendsumenddefcalc_pi(digits

  2. ruby - 如何在 buildr 项目中使用 Ruby 代码? - 2

    如何在buildr项目中使用Ruby?我在很多不同的项目中使用过Ruby、JRuby、Java和Clojure。我目前正在使用我的标准Ruby开发一个模拟应用程序,我想尝试使用Clojure后端(我确实喜欢功能代码)以及JRubygui和测试套件。我还可以看到在未来的不同项目中使用Scala作为后端。我想我要为我的项目尝试一下buildr(http://buildr.apache.org/),但我注意到buildr似乎没有设置为在项目中使用JRuby代码本身!这看起来有点傻,因为该工具旨在统一通用的JVM语言并且是在ruby中构建的。除了将输出的jar包含在一个独特的、仅限ruby​​

  3. ruby - 什么是填充的 Base64 编码字符串以及如何在 ruby​​ 中生成它们? - 2

    我正在使用的第三方API的文档状态:"[O]urAPIonlyacceptspaddedBase64encodedstrings."什么是“填充的Base64编码字符串”以及如何在Ruby中生成它们。下面的代码是我第一次尝试创建转换为Base64的JSON格式数据。xa=Base64.encode64(a.to_json) 最佳答案 他们说的padding其实就是Base64本身的一部分。它是末尾的“=”和“==”。Base64将3个字节的数据包编码为4个编码字符。所以如果你的输入数据有长度n和n%3=1=>"=="末尾用于填充n%

  4. ruby-on-rails - 如何在 ruby​​ 中使用两个参数异步运行 exe? - 2

    exe应该在我打开页面时运行。异步进程需要运行。有什么方法可以在ruby​​中使用两个参数异步运行exe吗?我已经尝试过ruby​​命令-system()、exec()但它正在等待过程完成。我需要用参数启动exe,无需等待进程完成是否有任何ruby​​gems会支持我的问题? 最佳答案 您可以使用Process.spawn和Process.wait2:pid=Process.spawn'your.exe','--option'#Later...pid,status=Process.wait2pid您的程序将作为解释器的子进程执行。除

  5. ruby - 如何在续集中重新加载表模式? - 2

    鉴于我有以下迁移:Sequel.migrationdoupdoalter_table:usersdoadd_column:is_admin,:default=>falseend#SequelrunsaDESCRIBEtablestatement,whenthemodelisloaded.#Atthispoint,itdoesnotknowthatusershaveais_adminflag.#Soitfails.@user=User.find(:email=>"admin@fancy-startup.example")@user.is_admin=true@user.save!ende

  6. ruby - 如何在 Ruby 中拆分参数字符串 Bash 样式? - 2

    我正在为一个项目制作一个简单的shell,我希望像在Bash中一样解析参数字符串。foobar"helloworld"fooz应该变成:["foo","bar","helloworld","fooz"]等等。到目前为止,我一直在使用CSV::parse_line,将列分隔符设置为""和.compact输出。问题是我现在必须选择是要支持单引号还是双引号。CSV不支持超过一个分隔符。Python有一个名为shlex的模块:>>>shlex.split("Test'helloworld'foo")['Test','helloworld','foo']>>>shlex.split('Test"

  7. ruby - 如何在 Lion 上安装 Xcode 4.6,需要用 RVM 升级 ruby - 2

    我实际上是在尝试使用RVM在我的OSX10.7.5上更新ruby,并在输入以下命令后:rvminstallruby我得到了以下回复:Searchingforbinaryrubies,thismighttakesometime.Checkingrequirementsforosx.Installingrequirementsforosx.Updatingsystem.......Errorrunning'requirements_osx_brew_update_systemruby-2.0.0-p247',pleaseread/Users/username/.rvm/log/138121

  8. java - 等价于 Java 中的 Ruby Hash - 2

    我真的很习惯使用Ruby编写以下代码:my_hash={}my_hash['test']=1Java中对应的数据结构是什么? 最佳答案 HashMapmap=newHashMap();map.put("test",1);我假设? 关于java-等价于Java中的RubyHash,我们在StackOverflow上找到一个类似的问题: https://stackoverflow.com/questions/22737685/

  9. ruby-on-rails - 如何在 ruby​​ 交互式 shell 中有多行? - 2

    这可能是个愚蠢的问题。但是,我是一个新手......你怎么能在交互式ruby​​shell中有多行代码?好像你只能有一条长线。按回车键运行代码。无论如何我可以在不运行代码的情况下跳到下一行吗?再次抱歉,如果这是一个愚蠢的问题。谢谢。 最佳答案 这是一个例子:2.1.2:053>a=1=>12.1.2:054>b=2=>22.1.2:055>a+b=>32.1.2:056>ifa>b#Thecode‘if..."startsthedefinitionoftheconditionalstatement.2.1.2:057?>puts"f

  10. ruby-on-rails - 如何在我的 Rails 应用程序 View 中打印 ruby​​ 变量的内容? - 2

    我是一个Rails初学者,但我想从我的RailsView(html.haml文件)中查看Ruby变量的内容。我试图在ruby​​中打印出变量(认为它会在终端中出现),但没有得到任何结果。有什么建议吗?我知道Rails调试器,但更喜欢使用inspect来打印我的变量。 最佳答案 您可以在View中使用puts方法将信息输出到服务器控制台。您应该能够在View中的任何位置使用Haml执行以下操作:-puts@my_variable.inspect 关于ruby-on-rails-如何在我的R

随机推荐