我正在制作一个练习应用程序，目标是从 RSS 提要中读取数据。

到目前为止一切顺利，除了我的应用程序遇到特殊字符问题。它读取节点内的第一个特殊字符，然后移动到下一个节点。

非常感谢任何帮助，对于后面的大代码块，我们深表歉意。

RSS 订阅 - www.usu.co.nz/usu-news/rss.xml

<title>Unitec hosts American film students</title>
<link>http://www.usu.co.nz/node/4640</link>
<description>&lt;p&gt;If you’ve been hearing American accents around the Mt Albert campus over the past week.</description>

显示代码

String xml = XMLFunctions.getXML();
Document doc = XMLFunctions.XMLfromString(xml);

NodeList nodes = doc.getElementsByTagName("item");

for (int i = 0; i < nodes.getLength(); i++) 
{                           
    Element e = (Element)nodes.item(i);
    Log.v("XMLTest", XMLFunctions.getValue(e, "title"));
    Log.v("XMLTest", XMLFunctions.getValue(e, "link"));
    Log.v("XMLTest", XMLFunctions.getValue(e, "description"));  
    Log.v("XMLTest", XMLFunctions.getValue(e, "pubDate"));
    Log.v("XMLTest", XMLFunctions.getValue(e, "dc:creator"));
}

读者代码

public class XMLFunctions 
{

public final static Document XMLfromString(String xml)
{

    Document doc = null;

    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
    try {

        DocumentBuilder db = dbf.newDocumentBuilder();

        InputSource is = new InputSource();
        is.setCharacterStream(new StringReader(xml));
        doc = db.parse(is); 

    } catch (ParserConfigurationException e) {
        System.out.println("XML parse error: " + e.getMessage());
        return null;
    } catch (SAXException e) {
        System.out.println("Wrong XML file structure: " + e.getMessage());
        return null;
    } catch (IOException e) {
        System.out.println("I/O exeption: " + e.getMessage());
        return null;
    }

    return doc;

}

/** Returns element value
  * @param elem element (it is XML tag)
  * @return Element value otherwise empty String
  */
 public final static String getElementValue( Node elem ) {
     Node kid;
     if(elem != null)
     {
         if (elem.hasChildNodes())
         {
             for(kid = elem.getFirstChild(); kid != null; kid = kid.getNextSibling())
             {
                 if( kid.getNodeType() == Node.TEXT_NODE  )
                 {
                     return kid.getNodeValue();
                 }
             }
         }
     }
     return "";
 }

 public static String getXML(){  
        String line = null;

        try {

            DefaultHttpClient httpClient = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost("http://www.usu.co.nz/usu-news/rss.xml");

            HttpResponse httpResponse = httpClient.execute(httpPost);
            HttpEntity httpEntity = httpResponse.getEntity();
            line = EntityUtils.toString(httpEntity);

        } catch (UnsupportedEncodingException e) {
            line = "<results status=\"error\"><msg>Can't connect to server</msg></results>";
        } catch (MalformedURLException e) {
            line = "<results status=\"error\"><msg>Can't connect to server</msg></results>";
        } catch (IOException e) {
            line = "<results status=\"error\"><msg>Can't connect to server</msg></results>";
        }

        return line;

}

public static int numResults(Document doc){     
    Node results = doc.getDocumentElement();
    int res = -1;

    try{
        res = Integer.valueOf(results.getAttributes().getNamedItem("count").getNodeValue());
    }catch(Exception e ){
        res = -1;
    }

    return res;
}

public static String getValue(Element item, String str) {       
    NodeList n = item.getElementsByTagName(str);        
    return XMLFunctions.getElementValue(n.item(0));
}
}

输出

Unitec hosts American film students
http://www.usu.co.nz/node/4640
<
Wed, 01 Aug 2012 05:43:22 +0000
Phillipa

最佳答案

您的代码仅从元素中提取第一个 子文本节点。 DOM 规范允许多个相邻的文本节点，所以我怀疑这里发生的是你的解析器代表 < , p , >其余文本作为(至少)四个单独的文本节点。您需要将节点连接成一个字符串，或者调用 normalize()在包含元素节点上(它修改 DOM 树以将相邻的文本节点合并为一个)。

有各种图书馆可以为您提供帮助。例如，如果您的应用程序使用 Spring 框架，则 org.springframework.util.xml.DomUtils有一个 getTextValue将从元素中提取完整文本值的静态方法。

关于Java 读取 XML - 在 '<' 特殊字符处停止，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/11825502/