您好，我正在尝试通过以下代码将 json 数据发布到 PHP 页面

URL obj = new URL(REST_URL);//(REST_URL + "?d_id=5&ds_remarks=" + et_text);
                    HttpURLConnection con = (HttpURLConnection) obj
                            .openConnection();
                    con.setRequestProperty("Content-type",
                            "application/json");
                    con.setRequestProperty("Accept", "application/json");
                    con.setRequestMethod("POST");
                    con.setDoInput(true);
                    con.setDoOutput(true);

                    String body = "{";
                    body+="d_id:2,ds_remarks:" + et_text;
                    System.out.println(et_text);
                    body+="}";

                    DataOutputStream wr = new DataOutputStream(
                            con.getOutputStream());
                    wr.writeBytes(body);
                    wr.flush();
                    wr.close();

                    BufferedReader in = new BufferedReader(
                            new InputStreamReader(con.getInputStream()));
                    String inputLine;
                    StringBuilder response = new StringBuilder();
                    while ((inputLine = in.readLine()) != null) {
                        response.append(inputLine);
                    }
                    in.close();
                    responseString = response.toString();
                    Log.d("GetCourse",
                            "Response Code: " + con.getResponseCode());
                    Log.d("Tag", "Response Stream : " + responseString);

                   con.disconnect();

                    System.out.println("=============================================");

                    return responseString;

我收到了对 PHP 页面的响应，但没有收到 PHP 页面上的参数 d_id 或 ds_remarks。我正在尝试使用此代码获取参数

$d_id   = urldecode($_REQUEST['d_id']);
$ds_remarks   = urldecode($_REQUEST['ds_remarks']);

帮我在PHP页面上获取参数。

谢谢

最佳答案

看来你没有像下面这样在 httppost 中添加你的参数:

List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2);  
nameValuePairs.add(new BasicNameValuePair("d_id", "example"));  
nameValuePairs.add(new BasicNameValuePair("ds_remarks", "example"));  
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

只打开一个连接不会发布您的参数。

编辑:

conn.setDoOutput(true);
List<NameValuePair> params = new ArrayList<NameValuePair>();
params.add(new BasicNameValuePair("d_id", "example"));
params.add(new BasicNameValuePair("ds_remarks", "example"));
OutputStream os = conn.getOutputStream();
BufferedWriter writer = new BufferedWriter(
        new OutputStreamWriter(os, "UTF-8"));
wr.write(formatQuery(params));
wr.flush();
wr.close();
os.close();
conn.connect();

private String formatQuery(List<NameValuePair> params) throws UnsupportedEncodingException
{
    StringBuilder result = new StringBuilder();
    boolean first = true;
    // append the params
    for (NameValuePair pair : params)
    {
        if (first)
            first = false;
        else
            result.append("&");
        result.append(URLEncoder.encode(pair.getName(), "UTF-8"));
        result.append("=");
        result.append(URLEncoder.encode(pair.getValue(), "UTF-8"));
    }
    return result.toString();
}

关于php - Android json 发布到 PHP 页面，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/32368063/