我有一个应用程序，我需要在其中移动成堆的按钮(就像将一叠卡片的一部分从一堆移动到另一堆)。我已经在 xml 布局中定义了所有按钮，并为所有按钮设置了触摸和拖动监听器。 我可以在屏幕上单独拖放任何按钮。但在某些情况下我需要做的是拖动堆叠在我同时单击的原始按钮顶部的其他按钮。 有没有办法“欺骗”或模拟按下另一个按钮(以便听众注册它)？ 谢谢 ***编辑于 2015 年 9 月 8 日 @覆盖 public boolean onTouch(View v, MotionEvent e) { //tosty("mclicking: "+mClicking); int 开始位置 = 0; 开关(e.getAction()和MotionEvent.ACTION_MASK){

    case MotionEvent.ACTION_DOWN:

        isWastePile=false;

        get_selected_deck(v); // determines which of 7 decks or layouts in the tablau you have
                                // clicked
        FromDeck = selecteddeck;
        FromDeckCard = deckcard;
        FromDeckButton = deckbutton;
        // if (!mClicking) {
        mClicking = true;
        //String piecetag = (String) v.getTag();

        // // IDEA!!!/ ///
        /*
         * I wrote a function that finds all the ImageButtons below where
         * the user clicked, and set them all to invisible. I then created a
         * new Linear Layout within the Linear Layout that the user clicked (during the ACTION_DOWN event),
         * and passed that into the Drag Shadow builder during the ACTION_MOVE event.
         * 
         * Once into the ACTION_DROP portion, I simply referenced global
         * variables to figure out if the user dropped in one or multiple
         * ImageButtons, and dealt with them accordingly.
         */

        //if (!isWastePile) {
        //draglayout.setClipChildren(false);
        lltemp = new LinearLayout(this);
        lltemp.setOrientation(LinearLayout.VERTICAL);
        LinearLayout.LayoutParams llparams = new LinearLayout.LayoutParams(
                LayoutParams.WRAP_CONTENT, LayoutParams.WRAP_CONTENT);

        llparams.setMargins(0, -52, 0, 0);
        lltemp.setLayoutParams(llparams);
        draglayout.addView(lltemp);


        for (int i = 0; i < deckstack_list[selecteddeck].size(); i++) {
            if (v == (draglayout.getChildAt(i))) {
                startpos = i;
                for (int o = i; o < deckstack_list[selecteddeck].size(); o++) {
                    // layout5.removeViewAt(o);
                    draglayout.getChildAt(o).setVisibility(View.GONE); // all
                                                                            // buttons
                                                                            // being
                    dragtempstack.push((Integer) deckstack_list[selecteddeck].get(o))   ;                                                   // dragged
                                                                            // to
                                                                            // invisible
                    // then recreate another linear layout within layout5
                    // and pass to dragshadow builder
                    // to do

                    // also set a GLOBAL variable with stack count (number
                    // of cards dragged)
                    lltemp.setClipChildren(false);
                    lltemp.addView(createtempButtons(o, startpos));


                }

            }
        }
        //} // end if wastepile check statement

        //tosty("dragtempstack size: "+dragtempstack.size());

        break;

    case MotionEvent.ACTION_MOVE:

        //tosty("Action MOVE");
        Log.i("ACTION Event: ", "ACTION MOVE");
        // v = layout5;


        v = lltemp;


        v.setVisibility(View.INVISIBLE);
        v.bringToFront();
        v.invalidate();
        v.setVisibility(View.VISIBLE);

        //DragShadowBuilder shadowBuilder = new View.DragShadowBuilder(v);
        DeckDragShadow shadowBuilder = new DeckDragShadow(v);
        v.startDrag(null, shadowBuilder, v, 0);


        correctDrag = false;

        break;

    private Button createtempButtons(final int i, final int startpos) {
    final Button b = new Button(this);

    b.setOnTouchListener(this);
    b.setOnDragListener(new DeckDragListener());

    b.setBackgroundResource(cardimagearray[dragdeckstack.get(i)]);

    float width = TypedValue.applyDimension(TypedValue.COMPLEX_UNIT_DIP,
            45, getResources().getDisplayMetrics());
    float height = TypedValue.applyDimension(TypedValue.COMPLEX_UNIT_DIP,
            61, getResources().getDisplayMetrics());

    LinearLayout.LayoutParams params = new LinearLayout.LayoutParams(
            (int) width, (int) height);
    float margTop = TypedValue.applyDimension(TypedValue.COMPLEX_UNIT_DIP,
            -36, getResources().getDisplayMetrics());

    if (i > startpos) {
        params.setMargins(0, -57, 0, 0);
    }

    b.setLayoutParams(params);

    // b.bringToFront();
    // b.invalidate();
    b.setVisibility(View.VISIBLE);

    return b;

最佳答案

与其尝试为每个按钮复制监听器，不如将按钮视为组。当您单击组中的一个按钮时，它会分成两组:上面有按钮的按钮和您要留下的按钮。然后将该组拖放到其他组中。

这些组可以是 LinearLayouts，正如 Templerschaf 所建议的:

• 您点击 LinearLayout
• 它注册了哪个项目
• 创建一个新的 LinearLayout，在正确的位置包含该项目下方的项目
• 删除被点击项目下方的项目并相应地调整大小
• 然后布局可以继续拖动
• 然后可以将它放到另一个 LinearLayout 上，它将项目添加到它自己的列表中

这很像 ListView 动画。见:

https://www.youtube.com/watch?v=_BZIvjMgH-Q

https://www.youtube.com/watch?v=mwE61B56pVQ

https://github.com/bauerca/drag-sort-listview/blob/master/library/src/com/mobeta/android/dslv/DragSortListView.java

关于java - 在java中拖动多个按钮 View ，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/32277809/