我正在尝试使用 socket.io 开发应用程序。有 2 台设备，当有人触摸设备 1 的屏幕时，我需要在设备 2 上看到一条消息。

这是 nodeJS 服务器代码(我使用的是 SocketIO v0.9.* 因为 socket.io-java-client 不支持 > 1.0.0 的版本)

var app = require('http').createServer()
    var io = require('socket.io').listen(1337);

    io.on('connection', function (socket) {
      socket.on('tiklama', function (data) {
        console.log(data);
        io.emit('tiklama', data);
      });
    });

和我的 Java 代码(click here 用于整个代码):

protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        final RelativeLayout anapanel = (RelativeLayout) findViewById(R.id.anapanel);
        final TextView tw = (TextView) findViewById(R.id.textView1);
        final TextView tw2 = (TextView) findViewById(R.id.textView2);
        final TextView tw4 = (TextView) findViewById(R.id.textView4);

        try {
            socket = new SocketIO("http://SERVERIPADDRESS:1337");
            socket.connect(new IOCallback() {
                @Override
                public void onMessage(JSONObject json, IOAcknowledge ack) {
                    try {
                        Log.d("x","Server said:" + json.toString(2));
                    } catch (JSONException e) {
                        e.printStackTrace();
                    }
                }

                @Override
                public void onMessage(String data, IOAcknowledge ack) {
                    Log.d("x","Server said: " + data);
                }

                @Override
                public void onError(SocketIOException socketIOException) {
                    Log.d("x","an Error occured");
                    socketIOException.printStackTrace();
                }

                @Override
                public void onDisconnect() {
                    Log.d("x","Connection terminated.");
                }

                @Override
                public void onConnect() {
                    Log.d("x","Connection established");
                }

                @Override
                public void on(String event, IOAcknowledge ack, Object... args) {
                    Log.d("x","Server triggered event '" + event + "'");

                    if(event.contentEquals("tiklama")) {
                    tw4.setText("Someone touched to device 1");
                    }
                }
            });

            // This line is cached until the connection is establisched.

        } catch (MalformedURLException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }



        anapanel.setOnTouchListener(new OnTouchListener() {

            @Override
            public boolean onTouch(View v, MotionEvent event) {
                // TODO Auto-generated method stub

                if (event.getAction() == MotionEvent.ACTION_DOWN){


                    socket.emit("tiklama", "someoneclicked");
                }

                return false;
            }
        });

    }

所以这是我的问题:两个设备都成功连接到 NodeJS 服务器，当我触摸设备上的屏幕时，我在服务器控制台上看到“someoneclicked”消息。但是第二台设备没有收到此消息，并且 LogCat 上没有发生任何事情。我怎样才能解决这个问题并与 socket.io 通信这两个设备？

最佳答案

由于您使用的是 0.9.* 版本的 socket.io，要广播消息，您需要使用 io.sockets.emit。 1.0 版本引入了快捷方式io.emit。

改变:

io.emit('tiklama', data);

到

io.sockets.emit('tiklama', data);

Migration from 0.9医生说:

Shortcuts In general there are some new shortcuts for common things. The old versions should still work, but shortcuts are nice.

Broadcasting to all clients in default namespace

Previously:

io.sockets.emit('eventname', 'eventdata');

Now:

io.emit('eventname', 'eventdata');

Neat. Note that in both cases, these messages reach all clients connected to the default ‘/’ namespace, but not clients in other namespaces.

关于java - 在 Android 上发送 socket.io 消息，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/26207380/