我有问题，如果我尝试允许系列系统警报，只工作一次，而下一次警报不“允许” 我用谷歌搜索了更多时间，并了解了那个帖子:( Xcode 7 UI Testing: how to dismiss a series of system alerts in code ) 什么都没有.. 不工作。 这是我当前的代码，第一个警报“允许”成功，下一个警报未检测到..

XCUIApplication *app = [[XCUIApplication alloc] init];
app.launchEnvironment = @{
        @"isUITest" : @YES,
        @"withFakeData" : fakeData
};
[app launch];


for (int i = 1; i <= self.possibleSystemAlerts; i++) {
    NSLog(@"%d", i);
    XCTestExpectation *expectation = [self expectationWithDescription:@"High Expectations"];
    id monitor = [self addUIInterruptionMonitorWithDescription:@"Push notifications" handler:^BOOL(XCUIElement *_Nonnull interruptingElement) {
        XCUIElement *element = interruptingElement;
        XCUIElement *allow = element.buttons[@"Allow"];
        XCUIElement *ok = element.buttons[@"OK"];

        if ([ok exists]) {
            [ok tap];
            [expectation fulfill];
            return YES;
        }

        if ([allow exists]) {
            [allow forceTap];
            [expectation fulfill];
            return YES;
        }
        return NO;
    }];
    [app tap];
    [self waitForExpectationsWithTimeout:6.0 handler:^(NSError *error) {
        if (error) {
            NSLog(@"Timeout Error: %@", error);
        }
    }];
    [self removeUIInterruptionMonitor:monitor];
}

最好的问候， 伊万。

更新:

好的，我找到了解决方案，如何在第一次警报后尝试关闭第二次(感谢这个网站:http://www.it1me.com/it-answers?id=32148965&s=Template:Viper&ttl=Xcode+7+UI+Testing%3A+how+to+dismiss+a+series+of+system+alerts+in+code)只需要返回 NO。

但是另一个问题...

    t =    10.18s                     Find: Descendants matching type Alert
    t =    10.18s                     Find: Identity Binding
    t =    11.19s                     Find the "Allow “MyApp” to access your location while you use the app?" Alert (retry 1)
    t =    11.19s                         Snapshot accessibility hierarchy for com.apple.springboard
    t =    11.26s                         Find: Descendants matching type Alert
    t =    11.26s                         Find: Identity Binding
    t =    12.27s                     Find the "Allow “MyApp” to access your location while you use the app?" Alert (retry 2)
    t =    12.27s                         Snapshot accessibility hierarchy for com.apple.springboard
    t =    12.33s                         Find: Descendants matching type Alert
    t =    12.34s                         Find: Identity Binding
    t =    12.42s                     Assertion Failure: UI Testing Failure - No matches found for "Allow “MyApp” to access your location while you use the app?" Alert
Query input was {(
    Alert 0x7febe8731630: traits: 72057602627862528, {{25.0, 193.0}, {270.0, 182.0}}, label: '“MyApp” Would Like to Send You Notifications'
)}

他尝试关闭第三个通知，而不是第二个，当然他没有发现这个系统警报...

最佳答案

在应用启动之前，一个接一个地创建警报处理程序。此外，请确保在与警报交互之前在应用程序的任何位置tap()。这是 Xcode 中的一个已知错误。

addUIInterruptionMonitor(withDescription:"First Dialog") { (alert) -> Bool in
    alert.buttons["Allow"].tap()
    return true
}

addUIInterruptionMonitor(withDescription:"Second Dialog") { (alert) -> Bool in
    alert.buttons["Allow"].tap()
    return true
}

addUIInterruptionMonitor(withDescription:"Third Dialog") { (alert) -> Bool in
    alert.buttons["Allow"].tap()
    return true
}

let app = XCUIApplication()
app.launch()

app.tap()
app.tap()
app.tap()

这三个点击将连续触发每个警报处理程序，而不会实际触发您应用中的任何事件。另请注意，每个中断处理程序未指定有关警报的任何内容，仅指定确认按钮。

关于ios - Xcode UI 测试允许系统警报系列，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/36753813/