我有这个:

• 110121 自然色 95 1570,40
• 110121 自然色 95 1570,40*
• 41,110 1 x 38,20 捷克克朗)[A] *
• ' 31,831 261,791 1308,61)
• >01572 PRAVO SO 17,00
• 1,000 ks x 17,00
• 1570,40

此输出的每一行都保存在列表中，我想获得编号 1570,40

对于这种格式，我的正则表达式看起来像这样

    "([1-9][0-9]*[\\.|,][0-9]{2})[^\\.\\d](.*)"
    "^([1-9][0-9]*[\\.|,][0-9]{2})$"

我有一个问题，如果找到了最后一行的 1570,40(通过第二个正则表达式)，还有 1570,40(来自末尾有 1570,40* 的行)但是第一行没有找到..做你知道问题出在哪里吗？

最佳答案

不确定我是否完全理解您的需求，但我认为您可以使用如下单词边界:

\b([1-9]\d*[.,]\d{2})\b

为了不匹配日期，你可以使用:

(?:^|[^.,\d])(\d+[,.]\d\d)(?:[^.,\d]|$)

解释:

The regular expression:

(?-imsx:(?:^|[^.,\d])(\d+[,.]\d\d)(?:[^.,\d]|$))

matches as follows:

NODE                     EXPLANATION
----------------------------------------------------------------------
(?-imsx:                 group, but do not capture (case-sensitive)
                         (with ^ and $ matching normally) (with . not
                         matching \n) (matching whitespace and #
                         normally):
----------------------------------------------------------------------
  (?:                      group, but do not capture:
----------------------------------------------------------------------
    ^                        the beginning of the string
----------------------------------------------------------------------
   |                        OR
----------------------------------------------------------------------
    [^.,\d]                  any character except: '.', ',', digits
                             (0-9)
----------------------------------------------------------------------
  )                        end of grouping
----------------------------------------------------------------------
  (                        group and capture to \1:
----------------------------------------------------------------------
    \d+                      digits (0-9) (1 or more times (matching
                             the most amount possible))
----------------------------------------------------------------------
    [,.]                     any character of: ',', '.'
----------------------------------------------------------------------
    \d                       digits (0-9)
----------------------------------------------------------------------
    \d                       digits (0-9)
----------------------------------------------------------------------
  )                        end of \1
----------------------------------------------------------------------
  (?:                      group, but do not capture:
----------------------------------------------------------------------
    [^.,\d]                  any character except: '.', ',', digits
                             (0-9)
----------------------------------------------------------------------
   |                        OR
----------------------------------------------------------------------
    $                        before an optional \n, and the end of
                             the string
----------------------------------------------------------------------
  )                        end of grouping
----------------------------------------------------------------------
)                        end of grouping
----------------------------------------------------------------------

关于Java - 获取数字格式的正则表达式，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/16168458/