我关注了 firebase documentation从上到下并为我的应用程序实现了一个简单的谷歌登录选项。但是，当我尝试登录时，该过程在选择谷歌帐户后停止，并导致 onActivityResult 方法内部出现错误:

if (requestCode == RC_SIGN_IN) {
       GoogleSignInResult result = Auth.GoogleSignInApi.getSignInResultFromIntent(data);
       if (result.isSuccess()) {
            // Google Sign In was successful, authenticate with Firebase
            GoogleSignInAccount account = result.getSignInAccount();
            firebaseAuthWithGoogle(account);
       } else {
            //THE CODE BREAKS HERE
            // Google Sign In failed, update UI appropriately
       }
}

代码在 if (result.isSuccess()) 条件处中断。为了进一步详细说明，这是我在阅读文档后实现的完整代码:

创建时:

public class TestLogin extends AppCompatActivity {

    private SignInButton mGoogleBtn;
    private static int RC_SIGN_IN = 226;
    private GoogleApiClient mGoogleApiClient;
    private  String TAG = "Checkmate";
    private FirebaseAuth mAuth;
    private FirebaseAuth.AuthStateListener mAuthListener;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_test_login);

        mAuth = FirebaseAuth.getInstance();
        mAuthListener = new FirebaseAuth.AuthStateListener() {
            @Override
            public void onAuthStateChanged(@NonNull FirebaseAuth firebaseAuth) {
                if(firebaseAuth.getCurrentUser() != null){
                    //success
                }
            }
        };

        mGoogleBtn = (SignInButton) findViewById(R.id.googleBtn);

        GoogleSignInOptions gso = new GoogleSignInOptions.Builder(GoogleSignInOptions.DEFAULT_SIGN_IN)
                .requestIdToken("MY_CLIENT_ID-MY_CLIENT_ID.apps.googleusercontent.com")
                .requestEmail()
                .build();

        mGoogleApiClient = new GoogleApiClient.Builder(getApplicationContext())
                .enableAutoManage(this, new GoogleApiClient.OnConnectionFailedListener() {
                    @Override
                    public void onConnectionFailed(@NonNull ConnectionResult connectionResult) {
                        //Failed
                    }
                })
                .addApi(Auth.GOOGLE_SIGN_IN_API, gso)
                .build();

        mGoogleBtn.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view) {
                statusMessage.setText("Loading..");
                signIn();
            }
        });
    }

登录方法:

当点击 Google Signin 按钮时调用 SignIn 方法:

    private void signIn() {
        Intent signInIntent = Auth.GoogleSignInApi.getSignInIntent(mGoogleApiClient);
        startActivityForResult(signInIntent, RC_SIGN_IN);
    }

onActivityResult:

onActivityResult 在点击按钮后收到结果时被调用。这是发生错误的地方:

    @Override
    public void onActivityResult(int requestCode, int resultCode, Intent data) {
        super.onActivityResult(requestCode, resultCode, data);

        // Result returned from launching the Intent from GoogleSignInApi.getSignInIntent(...);
        if (requestCode == RC_SIGN_IN) {
            GoogleSignInResult result = Auth.GoogleSignInApi.getSignInResultFromIntent(data);
            if (result.isSuccess()) {
                // Google Sign In was successful, authenticate with Firebase
                GoogleSignInAccount account = result.getSignInAccount();
                firebaseAuthWithGoogle(account);
            } else {
                //THE CODE BREAKS HERE
                // Google Sign In failed, update UI appropriately
            }
        }
    }

处理 Google 的 Firebase 登录代码:

此方法永远不会被调用，因为代码在 onActivityResult 条件下中断。

    private void firebaseAuthWithGoogle(final GoogleSignInAccount acct) {

        AuthCredential credential = GoogleAuthProvider.getCredential(acct.getIdToken(), null);
        mAuth.signInWithCredential(credential)
                .addOnCompleteListener(this, new OnCompleteListener<AuthResult>() {
                    @Override
                    public void onComplete(@NonNull Task<AuthResult> task) {
                        
                        // If sign in fails, display a message to the user. If sign in succeeds
                        // the auth state listener will be notified and logic to handle the
                        // signed in user can be handled in the listener.
                        if (!task.isSuccessful()) {
                            Toast.makeText(TestLogin.this, "Authentication failed.",
                                    Toast.LENGTH_SHORT).show();
                        }
                    }
                });
    }

    @Override
    protected void onStart() {
        super.onStart();
        mAuth.addAuthStateListener(mAuthListener);
    }

list :

Yes, I added the google_services.json file to the /app directory

Yes, I created a new OAuth Client Key in the Google Credentials page

这是我的 gradle:

dependencies {
    compile 'com.google.android.gms:play-services:9.6.1'
    compile 'com.google.firebase:firebase-core:9.6.1'
    compile 'com.google.firebase:firebase-database:9.6.1'
    compile 'com.google.firebase:firebase-auth:9.6.1'
    compile 'com.google.firebase:firebase-storage:9.6.1'
}
apply plugin: 'com.google.gms.google-services'

还有..

buildscript {
    repositories {
        jcenter()
    }
    dependencies {
        classpath 'com.android.tools.build:gradle:2.1.3'
        classpath 'com.google.gms:google-services:3.0.0'
    }
}

最佳答案

在我之前使用 Firebase FriendlyChat 的测试应用程序中，我在登录时遇到了类似的失败，但我已经通过转到 Google API 控制台(https://console.developers.google.com/apis/credentials?project=)然后下载“client_secret.json”解决了这个问题(在我的例子中，我需要要为您的 Android 客户端重命名下载的文件名“client_secret_xxxxx.json”)，请将此文件放入您的 AndroidStudio 项目中的“/src/main/resources”下(如果不存在则创建“resources”文件夹)然后尝试编译并运行您的 Android再次应用。

总结:您需要 2 个 json 文件:来自 Firebase 控制台的“google-services.json”和来自 Google API 控制台的“client_secret.json”。

希望这能解决您的问题。

关于Google 登录的 Android Firebase 身份验证失败，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/39900425/