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python - flask 操作错误 : unable to open database file using sqlite3

coder 2023-07-20 原文

我正在尝试将现有的 sqlite3 数据库连接到我正在构建的仪表板,但我遇到了一个我无法弄清楚如何解决的问题。我一直在努力将 Flask 文档和其他来源的内容拼凑起来,所以如果这里有任何看起来有点奇怪的地方,请随时给我打电话。可能是,我只是不知道 :)

代码:

from __future__ import with_statement
from contextlib import closing
from flask import Flask, render_template, request, session, g, redirect, url_for, abort, flash
import sqlite3

#config
DATABASE = '~/home/aaron/Dropbox/coding/webapp2/tmp/test.db'
DEBUG = True
SECRET_KEY = 'development key'
USERNAME = 'admin'
PASSWORD = 'default'

app = Flask(__name__)
app.config.from_object(__name__)

def connect_db():
    return sqlite3.connect(app.config['DATABASE']) # LINE 17


@app.before_request
def before_request():
    g.db = connect_db() # LINE 22

@app.teardown_request
def teardown_request(exception):
    if hasattr(g, 'db'):
        g.db.close()

# App seems to error out before app.route and if __name__=='__main__' block
# Everything in my app.route is commented out

完整的错误:

Traceback (most recent call last): File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1701, in call return self.wsgi_app(environ, start_response) File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1689, in wsgi_app response = self.make_response(self.handle_exception(e)) File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1687, in wsgi_app response = self.full_dispatch_request() File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1360, in full_dispatch_request rv = self.handle_user_exception(e) File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1356, in full_dispatch_request rv = self.preprocess_request() File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1539, in preprocess_request rv = func() File "/home/aaron/Dropbox/coding/webapp2/control.py", line 22, in before_request g.db = connect_db() File "/home/aaron/Dropbox/coding/webapp2/control.py", line 17, in connect_db return sqlite3.connect(app.config['DATABASE']) OperationalError: unable to open database file

127.0.0.1 - - [13/Oct/2012 13:55:48] "GET /?debugger=yes&cmd=resource&f=style.css HTTP/1.1" 200 - 127.0.0.1 - - [13/Oct/2012 13:55:48] "GET /?debugger=yes&cmd=resource&f=jquery.js HTTP/1.1" 200 - 127.0.0.1 - - [13/Oct/2012 13:55:48] "GET /?debugger=yes&cmd=resource&f=debugger.js HTTP/1.1" 200 - 127.0.0.1 - - [13/Oct/2012 13:55:48] "GET /?debugger=yes&cmd=resource&f=console.png HTTP/1.1" 200 - 127.0.0.1 - - [13/Oct/2012 13:55:48] "GET /?debugger=yes&cmd=resource&f=source.png HTTP/1.1" 200 - 127.0.0.1 - - [13/Oct/2012 13:55:49] "GET /favicon.ico HTTP/1.1" 500 -

Traceback (most recent call last): File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1701, in call return self.wsgi_app(environ, start_response) File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1689, in wsgi_app response = self.make_response(self.handle_exception(e)) File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1687, in wsgi_app response = self.full_dispatch_request() File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1360, in full_dispatch_request rv = self.handle_user_exception(e) File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1356, in full_dispatch_request rv = self.preprocess_request() File "/usr/local/lib/python2.7/dist-packages/flask/app.py", line 1539, in preprocess_request rv = func() File "/home/aaron/Dropbox/coding/webapp2/control.py", line 22, in before_request g.db = connect_db() File "/home/aaron/Dropbox/coding/webapp2/control.py", line 17, in connect_db return sqlite3.connect(app.config['DATABASE']) OperationalError: unable to open database file

看来问题出在这个配置行:

DATABASE = '~/home/aaron/Dropbox/coding/webapp2/tmp/test.db'

我的问题:

1) 为什么会抛出两次 OperationalError?

2) 为什么每个 OperationalError 都会调用第 17 行和第 22 行(在我上面的代码中有注释),即使这些是函数定义而不是函数调用?

3) 如果这是一个在指定路径上有数据的有效数据库,我该如何解决错误?

这些是我所引用的:

http://flask.pocoo.org/docs/tutorial/dbcon/#tutorial-dbcon

http://flask.pocoo.org/docs/tutorial/views/#tutorial-views

http://flask.pocoo.org/docs/patterns/sqlite3/

最佳答案

我认为问题出在 ~ 字符(在 shell 中有效但在 Python 中无效),因此您可能需要编写完整的绝对路径。我没有使用 Flask,但我建议在您的设置中设置 PROJECT_ROOT 常量,然后使用相对路径:

import os

PROJECT_ROOT = os.path.dirname(os.path.realpath(__file__))

DATABASE = os.path.join(PROJECT_ROOT, 'tmp', 'test.db')

关于python - flask 操作错误 : unable to open database file using sqlite3,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12876172/

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