草庐IT

Expected

全部标签

c++ - "Expected unqualified-id before ' 命名空间 '"错误

我有以下看似无害的代码:#ifndefUI_H#defineUI_H#includenamespaceui{//Displaysthemainmenu,showingloadedvocabularycards////ReturnsuponcompletionofdisplayvoiddisplayMainMenu();//...Morecodeliketheabove,justcommentsfollowedbyfunctions}#endif这给了我这个错误信息:filepath/ui.h:6:error:expectedunqualified-idbefore'namespace'

C++ - 错误 : expected unqualified-id before ‘using’

我有一个C++程序,当我尝试编译它时出现错误:calor.h|6|error:expectedunqualified-idbefore‘using’|这是calor类的头文件:#ifndef_CALOR_#define_CALOR_#include"gradiente.h"usingnamespacestd;classCalor:publicGradiente{public:Calor();Calor(inta);~Calor();intgetTemp();intgetMinTemp();voidsetTemp(inta);voidsetMinTemp(inta);voidmostra

c++ - 错误 : expected unqualified-id before 'if'

我用谷歌搜索了这个错误,直到脸色发青,但无法将任何结果与我的代码相关联。这个错误似乎通常是由错位或缺少大括号、parent等引起的。自从我编写任何C++以来也已经很长时间了,所以我可能遗漏了一些明显的、愚蠢的事情。这是我在QtCreator2.4.0中编写的QtMobile应用程序,基于Qt4.7.4(64位)构建于2011年12月20日11:14:33。#include#include#include#include#includeQFilefile("words.txt");QStringListwords;if(file.open(QIODevice::ReadOnly)){QT

android - 类型不匹配 : inferred type is String but Charset was expected in kotlin

我的主要Activity中有以下代码:varqNa_list=parseQuestions(loadJSONFromAsset("qna_list.json"))funloadJSONFromAsset(file_name:String):String?{varjson:String?=nulltry{valisis=assets.open(file_name)valsize=isis.available()valbuffer=ByteArray(size)isis.read(buffer)isis.close()json=String(buffer,"UTF-8")}catch(ex

android - 类型不匹配 : inferred type is String but Charset was expected in kotlin

我的主要Activity中有以下代码:varqNa_list=parseQuestions(loadJSONFromAsset("qna_list.json"))funloadJSONFromAsset(file_name:String):String?{varjson:String?=nulltry{valisis=assets.open(file_name)valsize=isis.available()valbuffer=ByteArray(size)isis.read(buffer)isis.close()json=String(buffer,"UTF-8")}catch(ex

windows - 在 Windows 上安装 Github- "Value does not fall within the expected range"

我正在尝试在我的Windows7笔记本电脑上安装Github,但每次运行GitHubSetup.exe时都会出现错误,提示“无法启动应用程序。请联系应用程序供应商。”。当我点击详细信息时,这是显示的文本:PLATFORMVERSIONINFOWindows:6.1.7601.65536(Win32NT)CommonLanguageRuntime:4.0.30319.18444System.Deployment.dll:4.0.30319.34244builtby:FX452RTMGDRclr.dll:4.0.30319.18444builtby:FX451RTMGDRdfdll.dll

json - {"errorMessages": ["Unexpected character (' '' (code 39)): expected a valid value

我从here找到了“使用POST查询”.并尝试使用类似命令的curl命令。引用this安装了curl适用于Windows。这是我的CURL字符串:curl-D--uadmin:password-XPOST-H"Content-Type:application/json"--data'{"jql":"project=CI","startAt":0,"maxResults":50,"fields":["summary","status","assignee"]}'"https://myclientname.atlassian.net/rest/api/2/search"这就是我正在做的事情

javascript - 超测错误 : expected '[]' response body, 得到 '[""]'

我不确定为什么会不断收到此错误。每当我运行npmtest时,我都会得到这个完整的错误:1)Listingsubscriptionson/subscriptionsReturnsinitialsubscriptions:Error:expected'[]'responsebody,got'[""]'aterror(node_modules\supertest\lib\test.js:299:13)atTest._assertBody(node_modules\supertest\lib\test.js:216:14)atTest._assertFunction(node_modules\

android - 类型不匹配 : inferred type is LoginActivity but LifecycleOwner was expected

我正在玩AndroidStudio-3.4Canary9的预览版。我从Configureyourproject窗口中选择了默认登录Activity选项,并提供了以下选项:Gradle同步没有报告错误,但是在构建编译时会产生以下错误:Typemismatch:inferredtypeisLoginActivitybutLifecycleOwnerwasexpected这是显示错误的代码fragment://Typemismatchatthis@LoginActivity,requiredLifeCycleOwner,found-LoginActivityloginViewModel.lo

android - 类型不匹配 : inferred type is LoginActivity but LifecycleOwner was expected

我正在玩AndroidStudio-3.4Canary9的预览版。我从Configureyourproject窗口中选择了默认登录Activity选项,并提供了以下选项:Gradle同步没有报告错误,但是在构建编译时会产生以下错误:Typemismatch:inferredtypeisLoginActivitybutLifecycleOwnerwasexpected这是显示错误的代码fragment://Typemismatchatthis@LoginActivity,requiredLifeCycleOwner,found-LoginActivityloginViewModel.lo