我正在使用我的uuid，如下所示:@Id@GeneratedValue(generator="uuid")@GenericGenerator(name="uuid",strategy="uuid")@Column(name="uuid",unique=true)privateStringuuid;但我收到了智能hibernate警告:Usingorg.hibernate.id.UUIDHexGeneratorwhichdoesnotgenerateIETFRFC4122compliantUUIDvalues;considerusingorg.hibernate.id.UUIDGener
