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swift - "Raw value for enum case is not unique"用于具有 Float 原始值的 Swift 枚举

根据TheSwiftProgrammingLanguage,我应该能够使用“字符串、字符或任何整数或float类型”的原始值创建一个Swift枚举。但是当我尝试时:enumBatteryVoltage:Float{casev3v7=3.7casev5v0=5.0casev7v4=7.4casev11v1=11.1casev12v0=12.0}...我得到一个编译错误:Rawvalueforenumcaseisnotunique在v7v4线上。它编译得很好,那个被注释掉了。但是啊,它看起来很独特。如果我将值设置为7.41、7.3或其他值,它可以正常编译。这是怎么回事?swift错误?

ios - ( swift )PrepareForSegue : fatal error: unexpectedly found nil while unwrapping an Optional value

细节ViewController:@IBOutletvarselectedBundesland:UILabel!表格ViewController:overridefuncprepareForSegue(segue:UIStoryboardSegue!,sender:AnyObject!){if(segue.identifier=="BackToCalculator"){varvc:FirstViewController=segue.destinationViewControllerasFirstViewControllervc.selectedBundesland.text="Test

ios - ( swift )PrepareForSegue : fatal error: unexpectedly found nil while unwrapping an Optional value

细节ViewController:@IBOutletvarselectedBundesland:UILabel!表格ViewController:overridefuncprepareForSegue(segue:UIStoryboardSegue!,sender:AnyObject!){if(segue.identifier=="BackToCalculator"){varvc:FirstViewController=segue.destinationViewControllerasFirstViewControllervc.selectedBundesland.text="Test

arrays - swift 2.2 : cannot convert value of type '[B]' to specified type '[A]'

我很困惑为什么这不起作用(这里没有太多要解释的):protocolA{varvalue:Int{getset}}structB:A{varvalue:Int}letarray:[B]=[B(value:10)]letsingleAValue:A=array[0]//extractingworksasexpectedvarprotocolArray:[A]=[]protocolArray.append(singleAValue)//wecanputthevalueinsidethe`protocolArray`withoutproblemsprint(protocolArray)letn

arrays - swift 2.2 : cannot convert value of type '[B]' to specified type '[A]'

我很困惑为什么这不起作用(这里没有太多要解释的):protocolA{varvalue:Int{getset}}structB:A{varvalue:Int}letarray:[B]=[B(value:10)]letsingleAValue:A=array[0]//extractingworksasexpectedvarprotocolArray:[A]=[]protocolArray.append(singleAValue)//wecanputthevalueinsidethe`protocolArray`withoutproblemsprint(protocolArray)letn

swift 泛型 : Cannot convert value of type to expected argument type

这是我的代码:protocolSomeProtocol{}classA:SomeProtocol{}funcf1(ofType:T.Type,listener:(T?)->Void){}funcf2(ofType:T.Type,listener:([T]?)->Void){}funcg(){letl1:(SomeProtocol?)->Void=...letl2:([SomeProtocol]?)->Void=...f1(ofType:A.self,listener:l1)//NOERRORf2(ofType:A.self,listener:l2)//COMPILEERROR:Cann

swift 泛型 : Cannot convert value of type to expected argument type

这是我的代码:protocolSomeProtocol{}classA:SomeProtocol{}funcf1(ofType:T.Type,listener:(T?)->Void){}funcf2(ofType:T.Type,listener:([T]?)->Void){}funcg(){letl1:(SomeProtocol?)->Void=...letl2:([SomeProtocol]?)->Void=...f1(ofType:A.self,listener:l1)//NOERRORf2(ofType:A.self,listener:l2)//COMPILEERROR:Cann

xcode - 快速关闭 : Cannot convert value of type '(_) -> Bool' to expected argument type

我在Swift中使用filter()方法,但遇到了一个我似乎无法在Playground上重现的问题。编辑:在此处上传示例项目:https://www.dropbox.com/s/5ce5uyxnpb0mndf/WeirdSwifty.zip?dl=0我有一个Card结构,其中包含一个CardType枚举:structCard{varname=""vartype:CardTypeenumCardType{caseRedcaseBlack}}还有一个Player类,它维护这些Card项目的数组:classPlayer{varhand:[Card]init(){hand=...}funcre

xcode - 快速关闭 : Cannot convert value of type '(_) -> Bool' to expected argument type

我在Swift中使用filter()方法,但遇到了一个我似乎无法在Playground上重现的问题。编辑:在此处上传示例项目:https://www.dropbox.com/s/5ce5uyxnpb0mndf/WeirdSwifty.zip?dl=0我有一个Card结构,其中包含一个CardType枚举:structCard{varname=""vartype:CardTypeenumCardType{caseRedcaseBlack}}还有一个Player类,它维护这些Card项目的数组:classPlayer{varhand:[Card]init(){hand=...}funcre

mybatisPlus返回Map类型的集合(两列字段,一列为key,一列为value)

1、自定义实现该类packagecom.linmain.dict.handle;importorg.apache.ibatis.session.ResultContext;importorg.apache.ibatis.session.ResultHandler;importjava.util.HashMap;importjava.util.Map;/***@Authorlinzhuoqi*@Date2023/3/9*@Eamil1580752420@qq.com*@Version*@Description新建一个mappedResults,每次感应到数据进来,处理下然后塞进去。*/@Supp