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文献阅读:LLaMA: Open and Efficient Foundation Language Models

文献阅读:LLaMA:OpenandEfficientFoundationLanguageModels1.文章简介2.模型训练1.训练数据2.模型结构3.模型训练1.Optimizer2.效率优化3.效果评估1.经典任务下效果1.CommenSenseReasoning2.Closed-bookQuestionAnswering3.ReadingComprehension4.Mathematicalreasoning5.Codegeneration6.MassiveMultitaskLanguageUnderstanding7.Evolutionofperformanceduringtrain

【开源AI大模型】WizardCoder: Empowering Code Large Language Models with Evol-Instruct

文章目录WizardCoder:EmpoweringCodeLargeLanguageModelswithEvol-InstructNewsComparingWizardCoderwiththeClosed-SourceModels.ComparingWizardCoderwiththeOpen-SourceModels.CallforFeedbacksUnofficialVideoIntroductionsContentsOnlineDemoFine-tuningInferenceEvaluationHumanEval

ios - swift 4 : multiple marker Google Map not display

我正在开发一个具有多个位置/标记的应用。我创建了一个结构letstates=[State(name:"Zoo1",long:2.276537,lat:102.2989),State(name:"Zoo2",long:2.2772141,lat:102.2984333),//theother51stateshere...]尝试循环但标记没有显示forstateinstates{letstate_marker=GMSMarker()state_marker.position=CLLocationCoordinate2D(latitude:state.lat,longitude:state.

swift - 错误 : Multiple commands produce . .. x86_64.swiftmodule

我正在将一个旧应用程序从swift3迁移到swift4,但遇到了这个错误:error:Multiplecommandsproduce'/Users/.../Library/Developer/Xcode/DerivedData/.../Debug-iphonesimulator/CompassV3.swiftmodule/x86_64.swiftmodule':1)Target'CompassV3'(project'VoidNavigator'):Ditto/Users/.../Library/Developer/Xcode/DerivedData/.../Debug-iphonesi

Maven工程 报 Diamond types are not supported at language level '5'

原文链接:https://blog.csdn.net/dongzhensong/article/details/88799477主要是参考了上面的做法就是目前使用的方法超过了选择的languagelevel的用法。我主要是在Modules–Languagelevel中解决的即在projectsettings中的modules里languagelevel要选择8以上。但是还有一个是要查看IDEA编辑器的JDK版本否则在run的时候会提示:Error:java:Compilationfailed:internaljavacompilererror所以需要在File-->Settings-->Bui

Xcode 6 测试版 : I'm not able to select Swift as language

我创建了一个新项目并选择了CocoaApp并按下了下一步,发现ObjectiveC是唯一可用的语言。我点击了帮助|XcodeMenu中的新功能,它说swift语言和lang支持是新功能。这里有什么问题吗?更新:我从Apple网站更新了产品。尽管Xcode附带的文档说Swift是此版本的一部分,但为什么我不能使用swift?对了,Xcode版本是:Version6.0(6A313)。 最佳答案 如theSwiftBlog中所述:TodayistheGMdateforSwiftoniOS.WehaveonemoreGMdatetogof

ios - 使用 Swift 3.0 调用 Google Cloud Natural Language API

我正在尝试根据此代码https://cloud.google.com/natural-language/reference/rest/v1/documents向Google的CloudNaturalLanguageAPI提出请求在Swift中,但我不能完全正确地理解语法?importFoundationimportSwiftyJSONclassGoogleNaturalLanguageParser{letsession=URLSession.sharedvargoogleAPIKey="XXX"vargoogleURL:URL{returnURL(string:"https://lan

swift - iOS : A specific function can be called from multiple threads/places, 但我希望每次调用都在队列中执行

我有一个函数readData从HealthKit读取数据,需要几秒钟才能执行。可以从多个线程/位置调用此函数,但我希望每次调用都在一个队列中执行,一次一个,而不是并行执行。有没有一种简单的方法可以使用GCD或OperationQueues在SwiftforiOS中实现这一点? 最佳答案 是的,串行DispatchQueue应该可以解决您的问题。确保您在需要访问它的每个函数都可以访问它的范围内创建它。letserialQueue=DispatchQueue(label:"serialQueue")serialQueue.async{/

Python vs. Go: The Great Showdown in Programming Languages

Thetechnologyindustryisevolvingatarapidpace,whichisparticularlytrueofprogramminglanguages.InApril,AnacondareleasedPyScript,allowingPythonprogramstoruninawebbrowser.Later,itisnoaccidentthatdevelopershavealsoappliedthesamestrategytoGo.Programminglanguageshaveuniquepropertiesandfeatures,amongwhichPytho

Could Perl 5.36 Lead to the Resurgence of This Once-dominant Programming Language?

OnMay28,2022,Perl5.36wasreleasedwitharangeofconvenientfeatures.Perlwasonceoneofthemostpopularprogramminglanguagesforwebdevelopmentworldwide;however,thereisabroaddivisionamongdeveloperstodayregardingit.FromtheTIOBEIndexforJune2022,itisapparentthatPerlisnolongerapopularprogramminglanguage.Perlappearso