为什么publishReplay(1).refCount()不为迟到的订阅者重播最后一个值?a=newRx.Subject();b=a.publishReplay(1).refCount();a.subscribe(function(x){console.log('timelysubscriber:',x)});a.next(1);b.subscribe(function(x){console.log('latesubscriber:',x)});预期输出:timelysubscribe:1latesubscriber:1实际输出timelysubscriber:1