我在PopupWindow中有一个ListView，我想单击列表中的第二个项目。我尝试了以下方法://OpenthepopupwindowonView(withId(R.id.popupwindow_open)).perform(click());现在弹出窗口出现了，我尝试了:onData(anything()).inAdapterView(withContentDescription("delete")).atPosition(1).perform(click());或者这个:onView(withContentDescription("delete"))).perform(clic