晚上好 - 我正在尝试根据存储在数据库中的帐户代码的分解文本字符串创建一个多维数组。帐户代码将具有不同的长度/深度。例如，下面数组中的 $test 与我从数据库中提取的结果类似:

$test = array( 
    '110|5100|120'    => 'Teacher Salaries',
    '110|5100|130'    => 'Other Professoinal Services',
    '110|5100|510|1'  => 'Primary Supplies',
    '110|5100|510|2'  => 'Intermediate Supplies', 
    '110|7300|110'    => 'Administrator Salaries', 
    '110|7300|510'    => 'Administrative Supplies', 
    '763|5100'        => 'Academic Grants'
); 
foreach($test AS $k => $v) { 
    $lvl = explode("|", $k);
    // Not sure what to do next... 
}

我想做的是创建一个函数，它将返回如下数组:

[110] => Array
    (
        [5100] => Array
            (
                [120] => Teacher Salaries
                [130] => Other Professional Services
                [510] => Array
                    (
                        [1] => Primary Supplies
                        [2] => Intermediate Supplies
                    )
            )
        [7300] => Array
            (
                [110] => Administrator Salaries
                [510] => Supplies
            )
    )
[763] => Array
    (
        [5100] => Academic Grants
    )

我能够想出一个函数，可以采用单个代码并将其正确分解为一个数组，但是当我尝试将它们合并在一起时，它们会丢失它们的 key 。这是我到目前为止所拥有的:

function expandedArray($codes, $value) { 
    $decoded = explode("|",$codes);
    RETURN expandedArraySub($decoded, $value); 
}
function expandedArraySub($decoded = array(), $value = Null) { 
    $k = array_pop($decoded); 
    $out[$k] = $value;
    if(is_array($decoded) && count($decoded) > 0) { $out = expandedArraySub($decoded, $out); }
    RETURN $out;
}

但是当我运行以下命令时，我没有像上面描述的那样得到我想要的，而是得到一个丢失“110”键的数组:

$r1 = expandedArray('110|5100|510|1', "Primary Supplies"); 
  // $r1 is now [ 110 => [5100 => [510 => [ 1 ] ] ] ]
$r2 = expandedArray('110|5100|510|2', 'Intermediate Supplies'); 
  // $r2 is now [ 110 => [5100 => [510 => [ 2 ] ] ] ]
$r = array_merge($r1, $r2); 

我得到的结果删除了第一个键，并没有像我希望的那样合并结果。这是我得到的:

[0] => Array
    (
        [5100] => Array
            (
                [510] => Array
                    (
                        [1] => Primary Supplies
                    )
            )
    )
[1] => Array
    (
        [5100] => Array
            (
                [510] => Array
                    (
                        [2] => Intermediate Supplies
                    )
            )
    )

非常感谢任何帮助!谢谢!

最佳答案

试试这段代码:

function getVal($data,$chain){
    $level = $data;
    for($i=0;$i<count($chain);$i++){
        if(isset($level[$chain[$i]]))
            $level = $level[$chain[$i]];
        else
            return null; // key does not exist, return null
    }
    return $level;
}

function setVal(&$data,$chain,$value){
    $level = &$data;
    for($i=0;$i<count($chain);$i++){
        $level = &$level[$chain[$i]]; // set reference (&) in order to change the value of the object
    }
    $level = $value;
}

要像这样使用它:

$output = array();
$test = array( 
    '110|5100|120'    => 'Teacher Salaries',
    '110|5100|130'    => 'Other Professoinal Services',
    '110|5100|510|1'  => 'Primary Supplies',
    '110|5100|510|2'  => 'Intermediate Supplies', 
    '110|7300|110'    => 'Administrator Salaries', 
    '110|7300|510'    => 'Administrative Supplies', 
    '763|5100'        => 'Academic Grants'
); 
foreach($test AS $k => $v) { 
    $lvl = explode("|", $k);
    setVal($output,$lvl,$v); 
}

$output 应具有所需的格式。

在 my previous post 中阅读有关此代码的更多信息

关于php - 在PHP中创建一个不确定深度的多维数组，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/46046631/