我有一个标记化文本列表 (list_of_words)，看起来像这样:

list_of_words = 
['08/20/2014',
 '10:04:27',
 'pm',
 'complet',
 'vendor',
 'per',
 'mfg/recommend',
 '08/20/2014',
 '10:04:27',
 'pm',
 'complet',
 ...]

我正试图从此列表中删除所有日期和时间实例。我试过使用 .remove() 函数，但无济于事。我试过将通配符(例如“../../....”)传递给我用来排序的停用词列表，但这没有用。我最终尝试编写以下代码:

for line in list_of_words:
    if re.search('[0-9]{2}/[09]{2}/[0-9]{4}',line):
        list_of_words.remove(line)

但这也行不通。如何从我的列表中删除日期或时间等格式的所有内容？

最佳答案

描述

^(?:(?:[0-9]{2}[:\/,]){2}[0-9]{2,4}|am|pm)$

此正则表达式将执行以下操作:

• 查找类似于日期 12/23/2016 和时间 12:34:56
的字符串
• 查找同样是 am 或 pm 的字符串，它们可能是源列表中之前时间的一部分

例子

现场演示

• 正则表达式:https://regex101.com/r/yE8oB9/2
• python :http://codepad.org/X9D3pd7s

示例列表

08/20/2014
10:04:27
pm
complete
vendor
per
mfg/recommend
08/20/2014
10:04:27
pm
complete

处理后列表

complete
vendor
per
mfg/recommend
complete

示例 Python 脚本

import re

SourceList = ['08/20/2014',
                 '10:04:27',
                 'pm',
                 'complete',
                 'vendor',
                 'per',
                 'mfg/recommend',
                 '08/20/2014',
                 '10:04:27',
                 'pm', 
                 'complete']

OutputList = filter(
    lambda ThisWord: not re.match('^(?:(?:[0-9]{2}[:\/,]){2}[0-9]{2,4}|am|pm)$', ThisWord),
    SourceList)


for ThisValue in OutputList:
  print ThisValue

说明

NODE                     EXPLANATION
----------------------------------------------------------------------
  ^                        the beginning of the string
----------------------------------------------------------------------
  (?:                      group, but do not capture:
----------------------------------------------------------------------
    (?:                      group, but do not capture (2 times):
----------------------------------------------------------------------
      [0-9]{2}                 any character of: '0' to '9' (2 times)
----------------------------------------------------------------------
      [:\/,]                   any character of: ':', '\/', ','
----------------------------------------------------------------------
    ){2}                     end of grouping
----------------------------------------------------------------------
    [0-9]{2,4}               any character of: '0' to '9' (between 2
                             and 4 times (matching the most amount
                             possible))
----------------------------------------------------------------------
   |                        OR
----------------------------------------------------------------------
    am                       'am'
----------------------------------------------------------------------
   |                        OR
----------------------------------------------------------------------
    pm                       'pm'
----------------------------------------------------------------------
  )                        end of grouping
----------------------------------------------------------------------
  $                        before an optional \n, and the end of the
                           string
----------------------------------------------------------------------

关于python - 如何从 Python 列表中删除日期，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/37473219/