阅读后this article其中指出:
After a device finishes its job , (IO operation)- it notifies the CPU via interrupt.
... ... ...
However, that “completion” status only exists at the OS level; the process has its own memory space that must be notified
... ... ...
Since the library/BCL is using the standard P/Invoke overlapped I/O system, it has already registered the handle with the I/O Completion Port (IOCP), which is part of the thread pool.
... ... ...
So an I/O thread pool thread is borrowed briefly to execute the APC, which notifies the task that it’s complete.
for (int i=0;i<1000;i++)
{
PingAsync_NOT_AWAITED(i); //notice not awaited !
}
最佳答案
Does it mean that it grabs a new thread pool thread for each completed IO operation ? Or is it a dedicated number of threads for this ?
Main 的进程中只有 3 个线程。 ,并且在请求实际工作之前,此数字不会增加。Does it mean that I'll have 1000 IOCP threadpool thread simultaneously ( sort of) running here , when all are finished ?
BeginXXX 方法或作为任务的延续)。如果您使用一个任务并且不等待它,那么该任务就会在那里结束,并且该线程将返回到线程池中。static void Main(string[] args) {
printThreadCounts();
var buffer = new byte[1024];
const int requestCount = 30;
int pendingRequestCount = requestCount;
for (int i = 0; i != requestCount; ++i) {
var stream = new FileStream(
@"C:\Windows\win.ini",
FileMode.Open, FileAccess.Read, FileShare.ReadWrite,
buffer.Length, FileOptions.Asynchronous
);
stream.BeginRead(
buffer, 0, buffer.Length,
delegate {
Interlocked.Decrement(ref pendingRequestCount);
Thread.Sleep(Timeout.Infinite);
}, null
);
}
do {
printThreadCounts();
Thread.Sleep(1000);
} while (Thread.VolatileRead(ref pendingRequestCount) != 0);
Console.WriteLine(new String('=', 40));
printThreadCounts();
}
private static void printThreadCounts() {
int completionPortThreads, maxCompletionPortThreads;
int workerThreads, maxWorkerThreads;
ThreadPool.GetMaxThreads(out maxWorkerThreads, out maxCompletionPortThreads);
ThreadPool.GetAvailableThreads(out workerThreads, out completionPortThreads);
Console.WriteLine(
"Worker threads: {0}, Completion port threads: {1}, Total threads: {2}",
maxWorkerThreads - workerThreads,
maxCompletionPortThreads - completionPortThreads,
Process.GetCurrentProcess().Threads.Count
);
}
Worker threads: 0, Completion port threads: 0, Total threads: 3
Worker threads: 0, Completion port threads: 8, Total threads: 12
Worker threads: 0, Completion port threads: 9, Total threads: 13
Worker threads: 0, Completion port threads: 11, Total threads: 15
Worker threads: 0, Completion port threads: 13, Total threads: 17
Worker threads: 0, Completion port threads: 15, Total threads: 19
Worker threads: 0, Completion port threads: 17, Total threads: 21
Worker threads: 0, Completion port threads: 19, Total threads: 23
Worker threads: 0, Completion port threads: 21, Total threads: 25
Worker threads: 0, Completion port threads: 23, Total threads: 27
Worker threads: 0, Completion port threads: 25, Total threads: 29
Worker threads: 0, Completion port threads: 27, Total threads: 31
Worker threads: 0, Completion port threads: 29, Total threads: 33
========================================
Worker threads: 0, Completion port threads: 30, Total threads: 34
stream.BeginRead(
buffer, 0, buffer.Length,
ar => {
stream.EndRead(ar);
Interlocked.Decrement(ref pendingRequestCount);
}, null
);
Worker threads: 0, Completion port threads: 0, Total threads: 3
Worker threads: 0, Completion port threads: 1, Total threads: 11
========================================
Worker threads: 0, Completion port threads: 0, Total threads: 11
FileOptions.Asynchronous至 FileOptions.None .这使得文件访问同步,异步操作将在工作线程上完成,而不是使用完成端口:Worker threads: 0, Completion port threads: 0, Total threads: 3
Worker threads: 8, Completion port threads: 0, Total threads: 15
Worker threads: 9, Completion port threads: 0, Total threads: 16
Worker threads: 10, Completion port threads: 0, Total threads: 17
Worker threads: 11, Completion port threads: 0, Total threads: 18
Worker threads: 12, Completion port threads: 0, Total threads: 19
Worker threads: 13, Completion port threads: 0, Total threads: 20
Worker threads: 14, Completion port threads: 0, Total threads: 21
Worker threads: 15, Completion port threads: 0, Total threads: 22
Worker threads: 16, Completion port threads: 0, Total threads: 23
Worker threads: 17, Completion port threads: 0, Total threads: 24
Worker threads: 18, Completion port threads: 0, Total threads: 25
Worker threads: 19, Completion port threads: 0, Total threads: 26
Worker threads: 20, Completion port threads: 0, Total threads: 27
Worker threads: 21, Completion port threads: 0, Total threads: 28
Worker threads: 22, Completion port threads: 0, Total threads: 29
Worker threads: 23, Completion port threads: 0, Total threads: 30
Worker threads: 24, Completion port threads: 0, Total threads: 31
Worker threads: 25, Completion port threads: 0, Total threads: 32
Worker threads: 26, Completion port threads: 0, Total threads: 33
Worker threads: 27, Completion port threads: 0, Total threads: 34
Worker threads: 28, Completion port threads: 0, Total threads: 35
Worker threads: 29, Completion port threads: 0, Total threads: 36
========================================
Worker threads: 30, Completion port threads: 0, Total threads: 37
ThreadPool.SetMinThreads的使用确保最少数量的线程可用于完成请求。如果我们回到 FileOptions.Asynchronous并添加 ThreadPool.SetMinThreads(50, 50)到 Main我们的玩具程序,结果是:Worker threads: 0, Completion port threads: 0, Total threads: 3
Worker threads: 0, Completion port threads: 31, Total threads: 35
========================================
Worker threads: 0, Completion port threads: 30, Total threads: 35
关于c# - IOCP 线程 - 澄清?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28690815/
我收到这个错误:RuntimeError(自动加载常量Apps时检测到循环依赖当我使用多线程时。下面是我的代码。为什么会这样?我尝试多线程的原因是因为我正在编写一个HTML抓取应用程序。对Nokogiri::HTML(open())的调用是一个同步阻塞调用,需要1秒才能返回,我有100,000多个页面要访问,所以我试图运行多个线程来解决这个问题。有更好的方法吗?classToolsController0)app.website=array.join(',')putsapp.websiteelseapp.website="NONE"endapp.saveapps=Apps.order("
如何在ruby中调用C#dll? 最佳答案 我能想到几种可能性:为您的DLL编写(或找人编写)一个COM包装器,如果它还没有,则使用Ruby的WIN32OLE库来调用它;看看RubyCLR,其中一位作者是JohnLam,他继续在Microsoft从事IronRuby方面的工作。(估计不会再维护了,可能不支持.Net2.0以上的版本);正如其他地方已经提到的,看看使用IronRuby,如果这是您的技术选择。有一个主题是here.请注意,最后一篇文章实际上来自JohnLam(看起来像是2009年3月),他似乎很自在地断言RubyCL
我正在尝试在Ruby中复制Convert.ToBase64String()行为。这是我的C#代码:varsha1=newSHA1CryptoServiceProvider();varpasswordBytes=Encoding.UTF8.GetBytes("password");varpasswordHash=sha1.ComputeHash(passwordBytes);returnConvert.ToBase64String(passwordHash);//returns"W6ph5Mm5Pz8GgiULbPgzG37mj9g="当我在Ruby中尝试同样的事情时,我得到了相同sha
C#实现简易绘图工具一.引言实验目的:通过制作窗体应用程序(C#画图软件),熟悉基本的窗体设计过程以及控件设计,事件处理等,熟悉使用C#的winform窗体进行绘图的基本步骤,对于面向对象编程有更加深刻的体会.Tutorial任务设计一个具有基本功能的画图软件**·包括简单的新建文件,保存,重新绘图等功能**·实现一些基本图形的绘制,包括铅笔和基本形状等,学习橡皮工具的创建**·设计一个合理舒适的UI界面**注明:你可能需要先了解一些关于winform窗体应用程序绘图的基本知识,以及关于GDI+类和结构的知识二.实验环境Windows系统下的visualstudio2017C#窗体应用程序三.
我正在尝试使用ruby编写一个双线程客户端,一个线程从套接字读取数据并将其打印出来,另一个线程读取本地数据并将其发送到远程服务器。我发现的问题是Ruby似乎无法捕获线程内的错误,这是一个示例:#!/usr/bin/rubyThread.new{loop{$stdout.puts"hi"abc.putsefsleep1}}loop{sleep1}显然,如果我在线程外键入abc.putsef,代码将永远不会运行,因为Ruby将报告“undefinedvariableabc”。但是,如果它在一个线程内,则没有错误报告。我的问题是,如何让Ruby捕获这样的错误?或者至少,报告线程中的错误?
我是ruby的新手,我认为重新构建一个我用C#编写的简单聊天程序是个好主意。我正在使用Ruby2.0.0MRI(Matz的Ruby实现)。问题是我想在服务器运行时为简单的服务器命令提供I/O。这是从示例中获取的服务器。我添加了使用gets()获取输入的命令方法。我希望此方法在后台作为线程运行,但该线程正在阻塞另一个线程。require'socket'#Getsocketsfromstdlibserver=TCPServer.open(2000)#Sockettolistenonport2000defcommandsx=1whilex==1exitProgram=gets.chomp
我有一个使用PDFKit呈现网页的pdf版本的Rails应用程序。我使用Thin作为开发服务器。问题是当我处于开发模式时。当我使用“bundleexecrailss”启动我的服务器并尝试呈现任何PDF时,整个过程会陷入僵局,因为当您呈现PDF时,会向服务器请求一些额外的资源,如图像和css,看起来只有一个线程.如何配置Rails开发服务器以运行多个工作线程?非常感谢。 最佳答案 我找到的最简单的解决方案是unicorn.geminstallunicorn创建一个unicorn.conf:worker_processes3然后使用它:
所以,Ruby1.9.1现在是declaredstable.Rails应该与它一起工作,并且正在慢慢地将gem移植到它。它具有native线程和全局解释器锁(GIL)。自从GIL到位后,原生线程是否比1.9.1中的绿色线程有任何优势? 最佳答案 1.9中的线程是原生的,但它们被“放慢了速度”,一次只允许一个线程运行。这是因为如果线程真的并行运行,它会混淆现有代码。优点:IO现在在线程中是异步的。如果一个线程阻塞在IO上,那么另一个线程将继续执行直到IO完成。C扩展可以使用真正的线程。缺点:任何非线程安全的C扩展都可能存在使用Thre
我在一个ruby文件中有一个函数可以像这样写入一个文件File.open("myfile",'a'){|f|f.puts("#{sometext}")}这个函数在不同的线程中被调用,使得像上面这样的文件写入不是线程安全的。有谁知道如何以最简单的方式使这个文件写入线程安全?更多信息:如果重要的话,我正在使用rspec框架。 最佳答案 您可以通过File#flock给锁File.open("myfile",'a'){|f|f.flock(File::LOCK_EX)f.puts("#{sometext}")}
我如何做Ruby方法"Flatten"RubyMethod在C#中。此方法将锯齿状数组展平为一维数组。例如:s=[1,2,3]#=>[1,2,3]t=[4,5,6,[7,8]]#=>[4,5,6,[7,8]]a=[s,t,9,10]#=>[[1,2,3],[4,5,6,[7,8]],9,10]a.flatten#=>[1,2,3,4,5,6,7,8,9,10 最佳答案 递归解决方案:IEnumerableFlatten(IEnumerablearray){foreach(variteminarray){if(itemisIEnume