我在cython中编写了以下函数来估计对数似然@cython.boundscheck(False)@cython.wraparound(False)deflikelihood(doublem,doublec,np.ndarray[np.double_t,ndim=1,mode='c']r_mpcnotNone,np.ndarray[np.double_t,ndim=1,mode='c']gtannotNone,np.ndarray[np.double_t,ndim=1,mode='c']gcrsnotNone,np.ndarray[np.double_t,ndim=1,mode='c'